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xx x x???; 3 . 41d1xx??; 4 . 2d3 si nxx??; 5 . d2 sin c o s 5xxx ???; 6 . 11d11xxx????? ; 7 . 1d1xxxx???; 8 . 243d( 1 ) ( 1 )xxx ??? . 三、求下列不定積分(用以前學(xué)過的方法): 1. ? ?3d1xxx??; 2 . 1 c o sds inxxxx???; 3 . 42d1xxx ??; 4 . 23si ndc osxxx?; 5 . 382d( 1 )xxx??; 6 . sind1 sinxxx??; 7 . 33d()xxx x x??; 8 . 2d( 1 )xxxexe ??; 9 . 22[ l n ( 1 ) ] dx x x???; 10. 21 a r c s i n dx x x??; 11. s in c o sds in c o sxxxxx ??; 12. d( ) ( )xx a b x???. 二、 1 . Cxxx????34)3)(1()2(ln21; 2 . Cxxxx????a r c t a n21)1()1(ln41224; 3 . )12a r c ta n (421212ln8222??????xxxxx C??? )12a r c t a n (42; 一、 1 . 2,1,1 ? ; 2 . 1,21,21 ; 3 . 22 12,12uduuu??; 4 . 初等函數(shù) . 練習(xí)題答案 4 . Cx?3t a n2a r c t a n321; 5 . Cx??512t a n3a r c t a n51; 6 . Cxxx ?????? )11l n (414; 7 . xxxx??????1111ln Cxx????11a r c t a n2 , 或 Cxxx????a rc s i n11ln2; 8 . Cxx???? 31123. 三、 1 . Cxx???? 11)1(212; 2 . Cxx ?? )s inln (; 3 . Cxxxx?????233213)1(; 4 . Cxxxx??? )t a nl n ( s e c21c o s2s i n2; 5 . Cxxx???484a r c t a n81)1(8; 6 . Cxx???2t a n12, 或 Cxxx ??? t a nse c ; 7 . Cxx??66)1(ln ; 8 . Ceexexxx????)1l n (1; 9 . Cxxxxxxx????????2)1l n (12)]1[ l n2222;