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【文章內(nèi)容簡介】 pendently sampling 3 studentsGiven p=, q=, then the probability values:{, , , }0 1 2 3Probability distributionFor samples of 1, p + qFor samples of 2, (p +q)2=p2 + 2pq + q2For samples of 3, (p +q)3=p3 + 3p2q + 3pq2 + q3…For samples of n, (p +q)n =The coefficients of the expanded terms Pascal’s triangle:1 11 2 11 3 3 11 4 6 4 11 5 10 10 5 1n12345…For samples of 4, (p+q)4 =p4+4p3q + 6p2q2 + 4pq3 + q4The binomial distribution(二項(xiàng)分布 )Pn(k) =Cnk pk qnk X 0 1 2 … k … nP qn npqn1 Cn2 p2 qn2 … Cnk pk qnk … pnDistribution series (分布列） Combinations ruleA sample of n elements to be chosen from a set of N elements. Then the number of different samples of n elements:Characteristics of the binomial distribution? There are only two possible outes on each trial, F or A? The trials are i
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