自動控制原理及系統(tǒng)仿真課程設(shè)計(編輯修改稿)
2025-02-09 17:43 本頁面
【文章內(nèi)容簡介】 num =1den = 04. 已知系統(tǒng)的開環(huán)傳遞函數(shù)為，繪制系統(tǒng)的Bode圖和Nyquist,并能夠求出系統(tǒng)的幅值裕度和相角裕度。MATLAB代碼：s=tf(39。s39。)G=5*(10*s+1)/(s*(s^2+*s+1)*(*s+1))figure(1)bode(G)gridfigure(2)nyquist(G)gridaxis([2 2 5 5])仿真結(jié)果：Transfer function:sTransfer function: 50 s + 5 s^4 + s^3 + s^2 + s5．考慮如圖所示的反饋控制系統(tǒng)的模型，各個模塊為，，用MATLAB語句分別得出開環(huán)和閉環(huán)系統(tǒng)的階躍響應(yīng)曲線。MATLAB代碼：num=[4]den=[1 2 3 4]G=tf(num,den)G0=feedback(G,1)step(G0)[y,t]=step(G0)plot(t,y)num=[1 3]den=[1 3]G=tf(num,den)G0=feedback(G,1)step(G0)[y,t]=step(G0)plot(t,y)num=[1]den=[ 1]G=tf(num,den)G0=feedback(G,1)step(G0)[y,t]=step(G0)plot(t,y)num1=[4]den1=[1 2 3 4]G1=tf(num1,den1)num2=[1 3]den2=[1 3]G2=tf(num2,den2)num3=[1]den3=[ 1]G3=tf(num3,den3)G=G1*G2G0=feedback(G,G3)step(G0)[y,t]=step(G0)plot(t,y)figure(2)step(G)[y,t]=step(G)plot(t,y)仿真結(jié)果：num =4den =1 2 3 4Transfer function: 4s^3 + 2 s^2 + 3 s + 4Transfer function: 4s^3 + 2 s^2 + 3 s + 8 y =+024 *0…… t = 0 . .…… num =1 3den =1 Transfer function:s 3s + 3Transfer functi
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