[工學(xué)]系統(tǒng)的狀態(tài)變量分析法-在線瀏覽
2025-03-10 13:06本頁(yè)面
【正文】 21321????環(huán)路：而有一個(gè)兩兩不接觸的：可知該系統(tǒng)有三個(gè)環(huán)路dgLcfLahg???321,::與此不接觸的環(huán)路為前向通路有一條xa hye bf cg d*.畫出圖示網(wǎng)絡(luò)的信號(hào)流圖 ,并用梅遜公式試求 H=Ur/E. 1c 2c解 :列出支路的電壓電流關(guān)系 )()()]()([)()]()([)()]()([)(2222111sRIsuscsususILssIsIsuscsusEsIRRLLL??????? )(te+ LRU1I2ILu???)(sRLs sc2 Rls? sc2?sc1?)(sE )(1 sI )(suL )(2 sI )(suRsc1 1kkkTsH ??? ?1)(32122221 )(1 RscLcsRcsLcsLc ???????113211 ?? ?RscLcT3212221321)(1)(RscLcsRcsLcLcRscLcsH??????)()()(,.*sxsysH ?轉(zhuǎn)移函數(shù)并用梅遜公式求其圖畫出如圖所示的信號(hào)流? ??1H3G1G3H2H2G+ + + )(sx)(sy5x4x1x3x2x? ?? ?? ??)(sx)(sy1x 5x4x3x2x1H3H2H1G?3G?2G?環(huán)路有三個(gè) : 33232321211GHHLGHLGHHL??????其中 L1與 L2為 兩兩不接觸的 環(huán)路 . ][][12132133223121GGHHHGHHGHGHH ?????? 前向通路只有一條 : 前向通路接觸由于所有環(huán)路都與該條前向通路的增益 3211: HHHg ?11 ??][1)(213212333212132111GGHHHGHGHHGHHHHHgsH????????167。 :模擬系統(tǒng)和原系統(tǒng)在輸入輸出關(guān)系上滿足同樣的微分方程或轉(zhuǎn)移函數(shù) . 間接編寫法第一類 :1器法加?1F2FY21)( FFsY ??No 名稱 方框圖 信號(hào)流圖 數(shù)學(xué)模型 器件放運(yùn)2器法乘a a )()( saFsy ?3?s1?器分積時(shí)頻p1s1)(sF )(sysx )0(sxssFsy )0()()( ??)()()()(1)()]()([)()()()(22221111sIRsvsysIscsvscsysvsIsIRsFsv???????? ?sc1 sc21 ?1R2R? 1v I2V)(sY??)(sF*.畫出圖示電路的模擬框圖 )(sF1R1VI2R2V)(sY＋－1c2c? assFsysHtfaydtdy????? 1)()()(),()(39。x xio xx ?39。39。39。39。39。x 39。x39。3x3x2x 1x??????????321xxx???x????????????39。239。39。,xxx???),. .2,1(139。39。32133221tfxxxxxxxx???????x21 410)( xxty ??)(1008191210001039。39。即時(shí)當(dāng)矩陣為零。寫出下列轉(zhuǎn)移函數(shù)的狀.?? ?53212260,1000,5972100001000010??????????????????????????????? CBA? ????????????????????????????????????????????????????????????????????432143214321532122601000597210000100001039。39。xxxxyexxxxxxxxD=0 2并聯(lián)模擬法 （級(jí)聯(lián)）并聯(lián)）12198104(423111)(23????????????ssssssssH串聯(lián)）()4)(3)(1()25(4?????ssss11?s31?s41?s)(1 sX)(2 sX)(3 sX?f y2－11 s1 2?
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