【導(dǎo)讀】路中斷概率被竊聽(tīng)了。所以我們認(rèn)為一個(gè)有限的反饋的情況的發(fā)射機(jī)所使用預(yù)定義的碼本被稱為用于波束形。方向的波束形成發(fā)送接收器。我們描述如何保密中斷概率來(lái)提高作為發(fā)射天線數(shù)的增加。我們進(jìn)一步的分析。了密增強(qiáng)碼書設(shè)計(jì)的影響，并提供在保密中斷概率的界限上的碼本波束形成。由于無(wú)線傳輸?shù)拈_(kāi)放性，它是脆弱的并有著潛在的安全威脅，如被動(dòng)竊聽(tīng)和主動(dòng)干擾。助于對(duì)被動(dòng)竊聽(tīng)的安全防范。射機(jī)）到“Bob”（接收者）。我們的目標(biāo)是利用Alice給Bob有限的反饋，量化基于碼本的傳輸波束成形的安。懷納[9]的研究表明，當(dāng)AliceEve通道是相對(duì)于物理降解Alice，Bob通道，Alice可以用一個(gè)。通過(guò)使用隨機(jī)編碼器的秘密消息映射。最大化作為AliceBob的差異，相互之間的信息和AliceEve在所有可能的輸入分布。為了簡(jiǎn)化這個(gè)問(wèn)題[12]

　　

【正文】 將（ 38）和（ 39）帶入（ 37），我們得到（ 15）的下界，然后用（ 35）得到（ 15）的上界，具體操作如上所述。 2. 樸素波束賦形 對(duì)于 單純 的波束賦形波束形成方向?yàn)閎b hhq?， 對(duì)于一個(gè) 單純 波束形成 的保密率 R 和傳輸功率 P 可以表示如下 ? ? ? ? ? ???? ??? ? dfhPRPPRP 2bnbsonbso ， （ 40） 使用公式（ 4）和引理 2 可得 ? ? ?????? ??? R e2e2bnbso 2 qHP r obhPRP ????， 我們會(huì)按照類似的步驟，由（ 36） ~（ 39）得到（ 14）。 致謝 感謝彭張節(jié)老師一直以來(lái)給予的熱心幫助和指導(dǎo)，此次在跟隨彭老師的學(xué)習(xí)中，我收獲良多。不僅豐富了自己的知識(shí)，更覺(jué)得自己能夠把所學(xué)付諸于實(shí)踐， 這些都多虧了彭老師的教導(dǎo)和同學(xué)們的幫助。我會(huì)繼續(xù)努力 ， 不辜負(fù)老師的期望和學(xué)校的教育。 參考文獻(xiàn) [1] D. Love, R. Heath Jr., and T. Strohmer, “Grassmannian beamforming for multipleinput multipleoutput wireless systems,” IEEE Trans. Inf. Theory, vol. 49, 20xx. [2] K. Mukkavilli, A. Sabharwal, E. Erkip, and B. Aazhang, “On beamforming with finite rate feedback in multipleantenna systems,” IEEE Trans. Inf. Theory, vol. 49, 20xx. [3] “IEEE Standard for Local and Metropolitan Area Networks Part 16: Air Interface for Fixed and Mobile Broadband Wireless Access Systems,” 20xx. [4] T. 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