【導(dǎo)讀】△ABC是等腰三角形分三種情況:①AB=AC,②AB=BC,③AC=BC,當(dāng)AB=AP時(shí),如圖,作OH⊥AB于點(diǎn)H,延長(zhǎng)AO交PB于點(diǎn)G;∵AB=AP,,∵AO過(guò)圓心,∴AG⊥PB,∴PG=BG,∠OAH=∠PAG,∵OH⊥AB,∴∠。AOH=∠BOH,AH=BH=4,∵∠AOB=2∠P,∴∠AOH=∠P,∵OA=5,AH=4,∴OH=3,∵∠OAH=∠PAG,∴sin∠OAH=sin∠PAG,∴358PG?,∴PG=245,∵∠AOH=∠P,∴cos. A.45°B.°或°C.45°或135°D.45°或°3.已知,等腰三角形的一條邊長(zhǎng)等于6cm,另一條邊長(zhǎng)等于4cm,到B時(shí),另一個(gè)點(diǎn)隨之停止.圖2是當(dāng)50??t時(shí)△BPQ的面積S與點(diǎn)P的運(yùn)動(dòng)。時(shí)間t的函數(shù)圖象.運(yùn)動(dòng)過(guò)程中,求出當(dāng)△BPQ是以BP為腰的等腰三角形時(shí)t的值.當(dāng)3<t≤5,點(diǎn)Q在D點(diǎn),BP=16﹣2t,當(dāng)∠PQB=90°時(shí),△BPQ∽△BAC,如圖②,,不合題意舍去;∵△BPQ∽△BCA,∴BP:BC=BQ:BA,即16211810tt???上,OC=12,BC=8,∠C=60°,點(diǎn)P以1個(gè)單位的速度從O點(diǎn)出發(fā)沿OC運(yùn)動(dòng),點(diǎn)Q以相。當(dāng)Q點(diǎn)在BC邊上運(yùn)動(dòng)時(shí),是否存在t值,使△OPQ為等腰三角形?與x軸分別相交于點(diǎn)A,①當(dāng)四邊形OMHN為矩形時(shí),求點(diǎn)H的坐標(biāo);