【正文】
0123113111211213112121??????????????????????????????ppKK x (2) 設離解度為 α2 , 332 211 22N2 2 ???????? RTVpnn i ? , p = p ? ?? ? ,離解度增加,解得整理得:, 6 1 3 2222222 ???????????????? ?????ppKK x (3) 設 離解度為 α3, 332 121 33N3 2 ???????? RTVpnn i ? , p = 2p ? ?? ? ,離解度不變,解得整理得:, 3 3323323 ????????????????? ?????ppKK x (4) 設離解度為 α4, PCl5(g) = PCl3(g) + Cl2(g) 1 α4 α4 α4 + y , ppyRT Vpyn i 22332 121 4444 ??????????? ?? ? ? ,離解度減少解得, 33 4444?????????? ?????????????????? ???? yppKK x 8. 解: (1) 平衡時 CaCO3 的摩爾數(shù) = = mol ∴ 熔融物中 a C O ???x (2) CaCO3(l) = CaO(s) + CO2(g), K = , ΔGm = RTln K 032 C a C OC a OCOm ????? ???G 333222 C a C OC a C O*C a C OCOCOCO lnln aRTppRT ???????????? ???? ,其中 0lnln323232 C a C OCOmC a C OCOC a C OC a OCOm ????????? ???????????? ?????? ap pRTGap pRTG則 ??? 所以 KRTppRTaRT lnlnln 23 COC a C O ?????????? 5 1 5 2 8 8 0 1 3 2 5 0 1 3 2 53C a C O ?????? xaa ?,