行列式按行列展開(1)(編輯修改稿)
2025-05-26 06:43 本頁面
【文章內(nèi)容簡介】 6115????5526????40? （降階法） 例 1 0532004140013202527102135?????D? ?53204140132021352152???????53241413252 ?????? 66027013210 ????? ? 66 27210 ????? .1080??二 . 利用展開定理計(jì)算行列式 例 2 計(jì)算四階 343332312423222143211111xxxxxxxxxxxxD ?解 1243412333122321423132312221413120001111xxxxxxxxxxxxxxxxxxxxxxxxD??????????)()()()()()()1(14241323122214413312214131211xxxxxxxxxxxxxxxxxxxxxxxx??????????? ?242322432141312111))()((xxxxxxxxxxxx ????范德蒙行列式 24242323242314131200111))()((xxxxxxxxxxxxxxxx????????)()()1)()()(( 244233242311141312 xxxxxxxxxxxxxxxx????????? ?43242314131211))()()()((xxxxxxxxxxxx ??????))()()()()(( 342423141312 xxxxxxxxxxxx ???????)(41jiijxx ?? ????343332312423222143211111xxxxxxxxxxxxD ?)(41jiijxx ?? ????因此四階范德蒙行列式的值為 ?????6427181691443121111151211312112232221321........................1...111???? nnnnnnnxxxxxxxxxxxx推廣： n階范德蒙行列式的值為 )(1jinijxx ?? ????例 3 求證 ??22211211aa
環(huán)評(píng)公示相關(guān)推薦
鄂ICP備17016276號(hào)-1