六種三角函數(shù)性質(zhì)-資料下載頁
2025-05-16 01:05本頁面
【正文】 tan(α/2)=177?！?(1cosα)/(1+cosα))=sinα/(1+cosα)=(1cosα)/sinαcot(α/2)=177?！?(1+cosα)/(1cosα))=(1+cosα)/sinαsec(α/2)=177?！?(2secα/(secα+1))csc(α/2)=177?！?(2secα/(secα1))輔助角公式：Asinα+Bcosα=√(A^2+B^2)sin(α+φ）（tanφ=B/A）Asinα+Bcosα=√(A^2+B^2)cos(αφ）（tanφ=A/B）萬能公式sin(a)= (2tan(a/2))/(1+tan^2(a/2))cos(a)= (1tan^2(a/2))/(1+tan^2(a/2))tan(a)= (2tan(a/2))/(1tan^2(a/2))降冪公式sin^2α=(1cos(2α))/2=versin(2α)/2cos^2α=(1+cos(2α))/2=covers(2α)/2tan^2α=(1cos(2α))/(1+cos(2α))三角和的三角函數(shù)：sin(α+β+γ)=sinαcosβcosγ+cosαsinβcosγ+cosαcosβsinγsinαsinβsinγcos(α+β+γ)=cosαcosβcosγcosαsinβsinγsinαcosβsinγsinαsinβcosγtan(α+β+γ)=(tanα+tanβ+tanγtanαtanβtanγ)/(1tanαtanβtanβtanγtanγtanα)其它公式1+sin(a)=(sin(a/2)+cos(a/2))^2 1sin(a)=(sin(a/2)cos(a/2))^2csc(a)=1/sin(a) sec(a)=1/cos(a)cos30=sin60sin30tanα+cotα=2/sin2αtanαcotα=2cot21+cos2α=2cos^2α1cos2α=2sin^2α1+sinα=[sin(α/2)+cos(α/2)]^21+sin(a)=(sin(a/2)+cos(a/2))^2 1sin(a)=(sin(a/2)cos(a/2))^2csc(a)=1/sin(a) sec(a)=1/cos(a)cos30=sin60sin30=cos60推導(dǎo)公式tanα+cotα=2/sin2αtanαcotα=2cot2α 1+cos2α=2cos^2α1cos2α=2sin^2α1+sinα=[sin(α/2)+cos(α/2)]^2 7 / 7
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