20xxap微積分calculus知識點總結(jié)-資料下載頁
【導讀】)(xf?＝y(tǒng)?)()(limlim00. a)Findy?x?0lim. pointB(x,f(x)).TheslopeofchordAB=axafxf??NowasB?A,x?aandthe. slopeofchordAB?slopeof. tangentatA.ax?)()(limis)(af?x=a.)(xf)(xf?nx1?nnx. xcosxsin?2cos1sec?)()(xvxu?)()(xvxu???)()(xvxu)()()()(xvxuxvxu???)()(xvxu2vvuvu???)0(?v. If)(ufy?where)(xuu?thendxdududydxdy?)()(xgexf?)()()(xgexfxg???)(ln)(xgxf?)()()(xgxgxf???)(ln)()(ln)()()()(xuxvxuxveexuxfxv???])()()()(ln)([)()(ln)(xuxuxvxuxvexfxuxv?????dydxdxdy1?])([1)(1????xfxf. .,xyarcsin?,yxsin?.,)(ty??,)(tx??→)(1xt???,)]([1xy????Implicitfunction:0))(,(?xyxF,0))(,(?xfxF.0-222??ayx,taytaxsincos??,t]2,0[??)()(lim)(02. n???????y=sinx)2sin(cos?????xxy. )2sin()(????nxyn. f(x)isincreasingonS?0)(??xfforallxinS,and. f(x)isdecreasingonS?0)(??xfforallxinS.Find)(xf?,andxwhichmake0)(??xf,wherenabx???Wenotethatas??n,???Wewrite????If0)(?xfforallxon[a,b]then. badxxf)(istheshadedarea.babadxxfdxxf)()]([. babadxxfcdxxcf)()(,cisanyconstant. cabacbdxxfdxxfdxxf)()()(. )()()()(aFbFxFdxxfbaba????,where??dxxfxF)()(. aadxxf0)(（f(x)odd）,????aaadxxfdxxf0)(2)((f(x)even). If0)(?xfonbxa??then??b. If)()(xgxf?onbxa??then???b. baavedxxfabf)(1. If)()(xfxF??,then???CxFdxxf)()(. Formulas:?????Cxndxxnn111,Caadxaxx???ln1. Cxinxdxcoss,???Cxxd
【正文】 ()()( ?? ? ??? baba ba dxxgdxxfdxxgxf )()()]()([ )()()()( aFbFxFdxxf baba ???? , where ?? dxxfxF )()( ?? ?aa dxxf 0)( （ f(x) odd） ,? ?? ?aa a dxxfdxxf 0 )(2)( (f(x)even) If 0)( ?xf on bxa ?? then ? ?ba dxxf 0)( If )()( xgxf ? on bxa ?? then ? ??ba ba dxxgdxxf )()( The average value of a function on an interval [a,b] ??? baa v e dxxfabf )(1 3. The infinite integral If )()( xfxF ?? , then ? ?? CxFdxxf )()( Formulas:? ??? ? Cxndxx nn 111 , Caadxa xx ??? ln1 ? ??? Cxin xd x c o ss , ? ?? Cxxd x s inc o s ,Cxx dx ???? c oslnt a n ,? ?? Cxx dx s i nlnc ot 吳靜彬 編寫 7 Cxxdx ???? a r c s in1 2 ( 12?x ), Cxxdx ???? a r c ta n1 2 U Substitution ? ? dxxgxgf )())(( substitution u=g(x) ? duuf )( Integration by Parts ? ??? vd uuvu d v
鄂ICP備17016276號-1