【文章內(nèi)容簡(jiǎn)介】
G 1H1H2H3G6H4G5G4G3G2R (s ) C (s )13 求解步驟之一(例 1) ? 前向通路數(shù): n= 1 G1H1H2H3G6H4G5G4G3G2R (s ) C (s )6543211 GGGGGGP ?14 求解步驟之二(例 1) ? 確定系統(tǒng)中的反饋回路數(shù) G 1H1H2H3G6H4G5G4G3G2R (s ) C (s )15 G1H1H2H3G6H4G5G4G3G2R (s ) C (s )反饋回路1 :L1 = -G1G2G3G4G5G6H1116 G1H1H2H3G6H4G5G4G3G2R (s ) C (s )反饋回路2 :L2 = G2G3H22117 G1H1H2H3G6H4G5G4G3G2R (s ) C (s )反饋回路3 :L3 = G4G5H312 318 G1H1H2H3G6H4G5G4G3G2R (s ) C (s )反饋回路4 :L4 = G3G4H412 3419 利用梅森公式求傳遞函數(shù) (1) ?????? ? ? ??411.1ikjijiiLLLLLL??求??????414321ii LLLLL4433542321654321 HGGHGGHGGHGGGGGG ?????))((