第8章3拉普拉斯逆變換-閱讀頁
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【正文】 ( ) ,stF s e 2]i Re s[? ( ) ,stF s e 2]i?2( 2 )s tesi?? 2si? 2( 2 )s tesi?? 2si??3( 2 )si? ?[ ( 2 ) 2 ]si t??tse2? 3( 2 )si? ?[ ( 2 ) 2 ]si t??tse1()32 16it?? 2tie 1()32 16it? ? ?2tie?32 i?2tie 2tie??16t? ?2tie 2tie?? 1?( s in 2 2 c o s 2 )t t t?的象原函數(shù) [] ?[] ?2si??16 [] ?例 10 求函數(shù) ()Fs 2( 1 )ss? ?解 ()Fs在 1 0s ?2 21ss??tse 2( 1 )ss? ?2 21ss??tse的留數(shù)為 1?在二級(jí)極點(diǎn) 2 1s ? 的留數(shù)為 1( 2 )ss ??? tse 1s?2[ ( 1 )s ??? tse 1( 2 )ss ?? ? ?stte1]s?2 te? 2 tte?()ft ? 12 te?? 2 tte?的象原函數(shù) 17 [] ??例 11 求函數(shù) ()Fs 1?解 ()Fs在 1 1s ??tse 3( 1 ) ( 1 )ss? ??tse的留數(shù)為 18?在三級(jí)極點(diǎn) 2 1s ? 的留數(shù)為 12!tse1s?18?te?te 2( 1 2 2 )tt??()ft ? 18? te? 18? 2( 1 2 2 )tt??te的象原函數(shù) ( 1)s ?3( 1)s ?1( 1 )s ??18 求函數(shù) ()Fs221 ses???解 ()Fs 21s?的象原函數(shù) 147頁 11.(13) L[ ] ()ft ()Fs?164頁 7. 延遲性質(zhì) 又 若 0t? 時(shí) ( ) 0,ft ? 則 0,???L[ ] ()ft ?? se ??? ()Fs22ses?? L[ ] t 21 ,s?L[ ] ()H t 1,s? L[ ] ()tH t 21 ,s?L[ ] ()22() Htt??21 ,s2se??象原函數(shù) ()ft ?t ( ( )22) Htt? ??
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