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高一化學方程式總結(jié)-文庫吧資料

2024-10-15 13:19本頁面
  

【正文】 2O1漂白粉漂白原理: Ca(ClO)2+H2O=2HClO+CaCO3↓1實驗室制Cl2(標出電子轉(zhuǎn)移): 4HCl+MnO2=Cl2↑+MnCl2+2H2O1NaI溶液中滴加氯水: 2NaI+Cl2=I2+2NaCl1Mg與熱水反應: Mg+2H2O=Mg(OH)2+H2↑1AlCl3中滴入NaOH: AlCl3+3NaOH=Al(OH)3↓+3NaCl 繼續(xù)滴入NaOH,沉淀溶解: NaOH+Al(OH)3=NaAlO2+2H2O1Al2O3與NaOH反應: Al2O3+2NaOH=2NaAlO2+H2O1實驗室制H2S FeS+H2SO4=FeSO4+H2S↑1H2O2中加少量MnO2:(標出電子轉(zhuǎn)移)2H2O2=2H2O+O2↑1H2S長期放置變渾濁或H2S不完全燃燒: 2H2S+O2=2H2O+2S↓H2S充分燃燒: 2H2S+3O2=2H2O+2SO22H2S與SO2反應:(標出電子轉(zhuǎn)移)2H2S+SO2=3S↓+2H2O2SO2通入氯水中褪色: SO2+Cl2+H2O=2HCl+H2SO42Cu與濃H2SO4,加熱:(標出電子轉(zhuǎn)移)Cu+2H2SO4=CuSO4+SO2↑+2H2O2木炭與濃H2SO4共熱:(標出電子轉(zhuǎn)移)C+2H2SO4=2H2O+CO2↑+2SO2↑2工業(yè)上制粗硅: SiO2+2C=Si+2CO↑ 條件:電爐內(nèi)2石英與NaOH反應: SiO2+2NaOH=Na2SiO3+H2O2玻璃工業(yè)上兩個反應: Na2CO3+SiO2=Na2SiO3+CO2↑ CaCO3+SiO2=CaSiO3+CO2↑2水玻璃中加CO2產(chǎn)生沉淀: 2H2O+Na2SiO3+CO2=Na2CO3+H4SiO4↓第二篇:高一化學方程式總結(jié)高一化學方程式總結(jié)一﹑非金屬單質(zhì)(F2,Cl2 , O2 , S, N2 , P , C , Si)1, 氧化性:F2 + H2 === 2HFF2 +Xe(過量)===XeF22F2(過量)+Xe===XeF4nF2 +2M===2MFn(表示大部分金屬)2F2 +2H2O===4HF+O22F2 +2NaOH===2NaF+OF2 +H2OF2 +2NaCl===2NaF+Cl2F2 +2NaBr===2NaF+Br2F2+2NaI ===2NaF+I2F2 +Cl2(等體積)===2ClF3F2(過量)+Cl2===2ClF37F2(過量)+I2 ===2IF7Cl2 +H2 ===2HCl3Cl2 +2P===2PCl3Cl2 +PCl3 ===PCl5Cl2 +2Na===2NaCl3Cl2 +2Fe===2FeCl3Cl2 +2FeCl2 ===2FeCl3Cl2+Cu===CuCl22Cl2+2NaBr===2NaCl+Br2Cl2 +2NaI ===2NaCl+I25Cl2+I2+6H2O===2HIO3+10HClCl2 +Na2S===2NaCl+SCl2 +H2S===2HCl+SCl2+SO2 +2H2O===H2SO4 +2HClCl2 +H2O2 ===2HCl+O22O2 +3Fe===Fe3O4 O2+K===KO2S+H2===H2S 2S+C===CS2S+Fe===FeS S+2Cu===Cu2S3S+2Al===Al2S3 S+Zn===ZnSN2+3H2===2NH3N2+3Mg===Mg3N2N2+3Ca===Ca3N2N2+3Ba===Ba3N2N2+6Na===2Na3NN2+6K===2K3NN2+6Rb===2Rb3NP2+6H2===4PH3P+3Na===Na3P2P+3Zn===Zn3P22.還原性S+O2===SO2S+O2===SO2S+6HNO3(濃)===H2SO4+6NO2+2H2O3S+4 HNO3(稀)===3SO2+4NO+2H2ON2+O2===2NO4P+5O2===P4O10(常寫成P2O5)2P+3X2===2PX3(X表示F2,Cl2,Br2)PX3+X2===PX5P4+20HNO3(濃)===4H3PO4+20NO2+4H2OC+2F2===CF4C+2Cl2===CCl42C+O2(少量)===2COC+O2(足量)===CO2C+CO2===2COC+H2O===CO+H2(生成水煤氣)2C+SiO2===Si+2CO(制得粗硅)Si(粗)+2Cl===SiCl4(SiCl4+2H2===Si(純)+4HCl)Si(粉)+O2===SiO2Si+C===SiC(金剛砂)Si+2NaOH+H2O===Na2SiO3+2H23,(堿中)歧化Cl2+H2O===HCl+HClO(加酸抑制歧化,加堿或光照促進歧化)Cl2+2NaOH===NaCl+NaClO+H2O2Cl2+2Ca(OH)2===CaCl2+Ca(ClO)2+2H2O3Cl2+6KOH(熱,濃)===5KCl+KClO3+3H2O3S+6NaOH===2Na2S+Na2SO3+3H2O4P+3KOH(濃)+3H2O===PH3+3KH2PO211P+15CuSO4+24H2O===5Cu3P+6H3PO4+15H2SO43C+CaO===CaC2+CO3C+SiO2===SiC+2CO二、金屬單質(zhì)(Na,Mg,Al,F(xiàn)e)的還原性2Na+H2===2NaH4Na+O2===2Na2O2Na2O+O2===2Na2O22Na+O2===Na2O22Na+S===Na2S(爆炸)2Na+2H2O===2NaOH+H22Na+2NH3===2NaNH2+H2 4Na+TiCl4(熔融)===4NaCl+Ti Mg+Cl2===MgCl2Mg+Br2===MgBr22Mg+O2===2MgOMg+S===MgSMg+2H2O===Mg(OH)2+H22Mg+TiCl4(熔融)===Ti+2MgCl2 Mg+2RbCl===MgCl2+2Rb 2Mg+CO2===2MgO+C2Mg+SiO2===2MgO+SiMg+H2S===MgS+H2Mg+H2SO4===MgSO4+H22Al+3Cl2===2AlCl34Al+3O2===2Al2O3(鈍化)4Al(Hg)+3O2+2xH2O===2()+4Hg4Al+3MnO2===2Al2O3+3Mn 2Al+Cr2O3===Al2O3+2Cr2Al+Fe2O3===Al2O3+2Fe 2Al+3FeO===Al2O3+3Fe2Al+6HCl===2AlCl3+3H2 2Al+3H2SO4===Al2(SO4)3+3H2 2Al+6H2SO4(濃)===Al2(SO4)3+3SO2+6H2O(Al,Fe在冷,濃的H2SO4,HNO3中鈍化)Al+4HNO(稀)===Al(NO3)3+NO+2H2O2Al+2NaOH+2H2O===2NaAlO2+3H22Fe+3Br2===2FeBr3Fe+I2===FeI2Fe+S===FeS 3Fe+4H2O(g)===Fe3O4+4H2Fe+2HCl===FeCl2+H2 Fe+CuCl2===FeCl2+CuFe+SnCl4===FeCl2+SnCl2(鐵在酸性環(huán)境下,不能把四氯化錫完全還原為單質(zhì)錫 Fe+SnCl2==FeCl2+Sn)三, 非金屬氫化物(HF,HCl,H2O,H2S,NH3)H2S+FeCl2===2NH3+2Na==2NaNH2+H2(NaNH2+H2O===NaOH+NH3)3,堿性:NH3+HCl===NH4ClNH3+HNO3===NH4NO32NH3+H2SO4===(NH4)2SO4NH3+NaCl+H2O+CO2===NaHCO3+NH4Cl(此反應用于工業(yè)制備小蘇打,蘇打)4,不穩(wěn)定性:2HF===H2+F22HCl===H2+Cl22H2O===2H2+O22H2O2===2H2O+O2H2S===H2+S2NH3===N2+3H21,還原性:四,非金屬氧化物4HCl(濃)+MnO2===MnCl2+Cl2+2H2O4HCl(g)+O2===2Cl2+2H2O16HCl+2KMnO4===2KCl+2MnCl2+5Cl2+8H2O1低價態(tài)的還原性:14HCl+K2Cr2O7===2KCl+2CrCl3+3Cl2+7H2O2SO2+O2===2SO32SO2+O2+2H2O===2H2SO42H2O+2F2===4HF+O2(這是SO2在大氣中緩慢發(fā)生的環(huán)境化學反應)SO2+Cl2+2H2O===H2SO4+2HClSO2+Br2+2H2O===H2SO4+2HBr2H2S+3O2(足量)===2SO2+2H2OSO2+I2+2H2O===H2SO4+2HI2H2S+O2(少量)===2S+2H2O2H2S+SO2===3S+2H2OSO2+NO2===SO3+NOH2S+H2SO4(濃)===S+SO2+2H2O2NO+O2===2NO23H2S+2HNO(稀)===3S+2NO+4H2O5H2S+2KMnO4+3H2SO4===2MnSO4+K2SO4+5S+8H2ONO+NO2+2NaOH===2NaNO23H2S+K2Cr2O7+4H2SO4===Cr2(SO4)3+K2SO4+3S+7H2O(用于制硝酸工業(yè)中吸收尾氣中的 NO和NO2)H2S+4Na2O2+2H2O===Na2SO4+6NaOH2CO+O2===2CO2CO+CuO===Cu+CO22NH3+3CuO===3Cu+N2+3H2O3CO+Fe2O3===2Fe+3CO2CO+H2O===CO2+H22NH3+3Cl2===N2+6HCl2氧化性:8NH3+3Cl2===N2+6NH4ClSO2+2H2S===3S+2H2OSO3+2KI===K2SO3+I24NH3+3O2(純氧)===2N2+6H2O4NH3+5O2===4NO+6H2ONO2+2KI+H2O===NO+I2+2KOH4NH3+6NO===5N2+6HO(用氨清除NO)(不能用淀粉KI溶液鑒別溴蒸氣和NO2)4NO2+H2S===4NO+SO3+H2ONaH+H2O===NaOH+H22NO2+Cu===4CuO+N2
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