考研化學(xué)物理化學(xué)必備題集統(tǒng)計熱力學(xué)答案(參考版)
2025-01-12 20:20本頁面
【正文】 K1K1K1K1K1 體系有四種分布： ―*― ν = 4 ―― ν = 4 ―― ν = 4 ―― ν = 4 ―― ν = 3 ―*― ν = 3 ―― ν = 3 ―― ν = 3 ―― ν = 2 ―― ν = 2 ―**― ν = 2 ―*― ν = 2 ―― ν = 1 ―*― ν = 1 ―― ν = 1 ―**― ν = 1 ―**― ν = 0 ―*― ν = 0 ―*― ν = 0 ―― ν = 0 體系總的微觀狀態(tài)數(shù) Ω = t1 + t2 + t3 + t4 = 3 + 6 + 3 + 3 = 15 (2) 經(jīng)典統(tǒng)計認(rèn)為，平衡分布時，能級 i 上分配的粒子數(shù)為： Ni = (Ngiexp(εi/kT)/q ，單維諧振子 gi = 1 N1/N0 = exp[(εiε0)/kT] = exp(hc?~ /kT) = exp( 2360/300) = 0 若以基態(tài)能量為零， N0/N = exp(ε0/kT)/q = 1/q(v) = 1exp(hc?~ /kT) = 10 = 1 9． 解：對雙原子 NO 在 300K 時， Vm = RT/p = 102 m3 I = (m1m2/(m1 + m2)r2 = 1046 kg)hv (ν = 0,1,2,3) 則由三個單維諧振子 組成的體系總能量 ε = εa + εb + εc = (νa + νa + νc + 189?！?i 故 Um = (L/q)( ?q/?β)V = L(?
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