【正文】
訓(xùn)練題 的值求已知)s i n ()2c o s (),0(42)c o s ()s i n (.6?????????????????????.0c o ss i n,0c o s,0s i n2087c o ss i n2::????????????????????????得又注意隱含的條件分析的值求已知變式題)s i n ()2cos (),0(1)cos ()s i n (2:?????????????????????),12(31c o s),1(31s i n:)2)(1()2(s i nc o s)s i n ()2c o s ()1(1c o ss i n2:??????????????xxxx??????????聯(lián)立得設(shè)由條件知分析能力訓(xùn)練題 ).( s i n,17c o s)( c o xfxxf 求若 ?.17s i n)1790c o s ()17903604c o s ()]90(17c o s [)]90[ c o s ()( s i n:xxxxxfxf????????????????分析).( c o s),(,)14s i n ()( s i n:xfZnxnxf求若變式題 ???六組誘導(dǎo)公式 .,:.))(90(2:符號看象限奇變偶不變記憶口訣各三角函數(shù)值兩套誘導(dǎo)公式可概括為 Zkkk ???? ??? ??????????t a n)t a n (c o s)c o s (s in)s in (??????????????t a n)t a n (c o s)c o s (s in)s in (?????????????????t a n)t a n (c o s)c o s (s in)s in (?????????????????t a n)2t a n (c o s)2c o s (s in)2s in (??????kkk??????si n)2c o s(c o s)2si n (??????????si n)2c o s(c o s)2si n (?????