控制系統(tǒng)仿真與cad(編輯修改稿)
2024-09-01 06:54 本頁(yè)面
【文章內(nèi)容簡(jiǎn)介】 z)*(11201/1250/z)*(11131/1250/z)*(14347/5000/z)/(1+1465160683/781229961/z)用圖形仿真方法(Simulink)分析單位加速度信號(hào)輸入時(shí)閉環(huán)系統(tǒng)動(dòng)態(tài)性能和穩(wěn)態(tài)性能。輸入：[N,D]=numden(simplify(Gcz))。numc=sym2poly(N)denc=sym2poly(D)[N,D]=numden(simplify(Guz))。numu=sym2poly(N)denu=sym2poly(D)t=0::1u=t.*t/2hold ondlsim(numc,denc,u)dlsim(numu,denu,u)hold off[N,D]=numden(simplify(Dyz))。numdy=sym2poly(N)dendy=sym2poly(D)有波紋最小拍程序仿真截圖：有波紋最小拍圖形仿真截圖：閉環(huán)系統(tǒng)輸出Gcz圖形仿真結(jié)果：控制器輸出U(z)圖形仿真圖：確定誤差脈沖傳遞函數(shù)Ge(z)形式,滿足單位速度信號(hào)輸入時(shí)閉環(huán)穩(wěn)態(tài)誤差為零和實(shí)際閉環(huán)系統(tǒng)穩(wěn)定的要求。Gez =(11/z)^2*(e0+e1/z+e2/z^2+e3/z^3+e4/z^4)1確定閉環(huán)脈沖傳遞函數(shù)Gc(z)形式，滿足控制器Dw(z)可實(shí)現(xiàn)、無(wú)波紋、最少拍和實(shí)際閉環(huán)系統(tǒng)穩(wěn)定的要求。Gez=(1z^1)^2*(b0+b1*z^1+b2*z^2+b3*z^3+b4*z^4)1根據(jù)1列寫方程組，求解Gc(z)和Ge(z)中的待定系數(shù)并最終求解Gc(z)和Ge(z) 。輸入：syms z a0 a1 b0 b1 b2 b3 b4Gez=(1z^1)^2*(b0+b1*z^1+b2*z^2+b3*z^3+b4*z^4)f1=subs(Gcz,z,1)1f2=subs(diff(Gcz,1),z,1)[a0j a1j]=solve(f1,f2)A=double([a0j a1j])Gcz=subs(Gcz,[a0 a1],A)Gez=(1z^1)^2*(b0+b1*z^1+b2*z^2+b3*z^3+b4*z^4)f3=subs(Gez,z,inf)1f4=subs(Gez,z,)1f5=subs(Gez,z,)1f6=subs(Gez,z,)1f7=subs(Gez,z,)1[b0j b1j b2j b3j b4j]=solve(f3,f4,f5,f6,f7)B=double([b0j b1j b2j b3j b4j])Gez=subs(Gez,[b0 b1 b2 b3 b4],B)結(jié)果：Gez=(11/z)^2*(1+4607117145708427/10995
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