控制系統(tǒng)仿真與cad實(shí)驗(yàn)報(bào)告(編輯修改稿)
2024-08-28 21:25 本頁(yè)面
【文章內(nèi)容簡(jiǎn)介】 s^10 + 3 s^9 + 55 s^8 + 175 s^7 + 300 s^6 + 1323 s^5 + 2656 s^4 + 3715 s^3 + 7732 s^2 + 5602 s + 1400 Continuoustime transfer function.9.s=tf(39。s39。)。T0=。T1=。T2=1。G=(s+1)^2*(s^2+2*s+400)/((s+5)^2*(s^2+3*s+100)*(s^2+3*s+2500))。Gd1=c2d(G,T0),Gd2=c2d(G,T1),Gd3=c2d(G,T2),step(G),figure,step(Gd1),figure,step(Gd2),figure,step(Gd3)Gd1 = z^5 z^4 + z^3 + z^2 z + z^6 z^5 + z^4 z^3 + z^2 z + Sample time: secondsDiscretetime transfer function.Gd2 = z^5 z^4 z^3 + z^2 z + z^6 z^5 + z^4 z^3 + z^2 z + Sample time: secondsDiscretetime transfer function.Gd3 = z^5 z^4 + z^3 + 05 z^2 z + z^6 z^5 z^4 z^3 + z^2 z + Sample time: 1 secondsDiscretetime transfer function.10.(a) G=tf(1,[1 2 1 2])。eig(G),pzmap(G)ans = + 系統(tǒng)為臨界穩(wěn)定。(b) G=tf(1,[6 3 2 1 1])。eig(G),pzmap(G)ans = + + 有一對(duì)共軛復(fù)根在右半平面，所以系統(tǒng)不穩(wěn)定。(c) G=tf(1,[1 1 3 1 2])。eig(G),pzmap(G)ans = 有兩根在右半平面，故系統(tǒng)不穩(wěn)定。11.(1) H=tf([3 2],[1 ])。pzmap(H),abs(eig(H39。))ans = 系統(tǒng)穩(wěn)定。(2) H=tf([3 ],[1 ])。pzmap(H),abs(eig(H39。))ans = 系統(tǒng)不穩(wěn)定。12.(1) A=[ 0 0 0。0 0 0。0 0 0。0 0 0 100。0 0 0 0 10]。B=[0 0 0 0 30]39。C=zeros(1,5)。D=0。G=ss(A,B,C,D),eig(G)G = a = x1 x2 x3 x4 x5 x1 0 0 0 x2 0 0 0 x3 0 0 0 x4 0 0 0 100 x5 0 0 0 0 10 b = u1 x1 0ans = x2 0 x3 0 x4 0 x5 30 c = x1 x2 x3 x4 x5 y1 0 0 0 0 0 d = u1 y1 0Continuoustime statespace model.系統(tǒng)穩(wěn)定。13. A=[5 2 0 0。 0 4 0 0。 3 2 4 1。 3 2 0 4]。 A=sym(A)。syms t。x=expm(A*t)*[1。2。0。1]x =4*exp(4*t) 3*exp(5*t)2*exp(4*t)12*exp(4*t) 18*exp(5*t) + 3*t*exp(4*t) 4*t^2*(exp(4*t)/(4*t) + exp(4*t)/(2*t^2)) + 8*t^2*(exp(4*t)/2 exp(4*t)/(2*t)) 16*t*(exp(4*t) exp(4*t)/(2*t))
環(huán)評(píng)公示相關(guān)推薦
鄂ICP備17016276號(hào)-1