【文章內(nèi)容簡介】 222 1 4 7 0 0 222 2 5 8 0 0 222 2 5 8 0 0 222 3 6 9 0 0 222 3 6 9 0 0 222 0 0 0 0 0 222 0 0 0 0 0 222 0 0 0 0 111 222 0 0 0 0 111 222 （3）合成擴展法B=ones(2,6) B = 1 1 1 1 1 1 1 1 1 1 1 1 AB_r=[A。B] AB_r = 1 4 7 0 0 222 2 5 8 0 0 222 3 6 9 0 0 222 0 0 0 0 0 222 0 0 0 0 111 222 1 1 1 1 1 1 1 1 1 1 1 1 AB_c=[A,B(:,1:5)39。] AB_c = 1 4 7 0 0 222 1 1 2 5 8 0 0 222 1 1 3 6 9 0 0 222 1 1 0 0 0 0 0 222 1 1 0 0 0 0 111 222 1 1 【】提取子數(shù)組，合成新數(shù)組。A A = 1 4 7 0 0 222 2 5 8 0 0 222 3 6 9 0 0 222 0 0 0 0 0 222 0 0 0 0 111 222 AB_BA=triu(A,1)+tril(A,1) AB_BA = 0 4 7 0 0 222 2 0 8 0 0 222 3 6 0 0 0 222 0 0 0 0 0 222 0 0 0 0 0 222 AB1=[A(1:2,end:1:1)。B(1,:)] AB1 = 222 0 0 7 4 1 222 0 0 8 5 2 1 1 1 1 1 1 【】單下標尋訪和reshape指令演示。clearA=reshape(1:16,2,8) A = 1 3 5 7 9 11 13 15 2 4 6 8 10 12 14 16 reshape(A,4,4) ans = 1 5 9 13 2 6 10 14 3 7 11 15 4 8 12 16 s=[1 3 6 8 9 11 14 16]。A(s)=0 A = 0 0 5 7 0 0 13 15 2 4 0 0 10 12 0 0 【】“對列（或行）同加一個數(shù)”三種的操作方法。clear,A=reshape(1:9,3,3) A = 1 4 7 2 5 8 3 6 9 b=[1 2 3]。A_b1=Ab([1 1 1],:) A_b1 = 0 2 4 1 3 5 2 4 6 A_b2=Arepmat(b,3,1) A_b2 = 0 2 4 1 3 5 2 4 6 A_b3=[A(:,1)b(1),A(:,2)b(2),A(:,3)b(3)] A_b3 = 0 2 4 1 3 5 2 4 6 【】邏輯函數(shù)的運用示例。randn(39。state39。,1),R=randn(3,6) R = L=abs(R)|abs(R) L = 0 0 0 1 0 0 1 1 1 1 0 1 0 1 0 0 0 1 R(L)=0 R = 0 0 0 0 0 0 0 0 s=(find(R==0))39。 s = 2 5 6 8 10 11 17 18 R(s)=111 R = [ii,jj]=find(R==111)。disp(ii39。),disp(jj39。) 2 2 3 2 1 2 2 31 2 2 3 4 4 6 6 高維數(shù)組 高維數(shù)組的創(chuàng)建【】“全下標”元素賦值方式創(chuàng)建高維數(shù)組演示。A(2,2,2)=1 A(:,:,1) =0 00 0A(:,:,2) =0 0 0 1 B(2,5,:)=1:3 B(:,:,1) = 0 0 0 0 0 0 0 0 0 1B(:,:,2) = 0 0 0 0 0 0 0 0 0 2B(:,:,3) = 0 0 0 0 0 0 0 0 0 3