高等數(shù)學(xué)11-4-1-經(jīng)營(yíng)管理(完整版)
【正文】 dxx 0 21ar c t an?? ?????????12)1(5131 1253nxxxx nn]1,1[??x? ??? x xdxx 0 1)1l n(?? ??????? ? nxxxxnn 132 )1(3121]1,1(??x例 3 .2c o ss i n)( 的冪級(jí)數(shù)展開成將 xxxxf ?解 xxxf 2c oss i n)( ? ]s in3[ s in21 x????? ?????????)!12()1(!51!31s in 1253nxxxxx nn)!12()1(21)!12()3()1(21 120120 ???????????????? nxnxnnnnnn??????? ??? ?????? xxn nnnn.)!12( )13()1(21 12120例 4 .)1l n ()( 2 的冪級(jí)數(shù)展開成將 xxxxf ???解 111ln)( 3 ???? xxxxf)1l n ()1l n ( 3 xx ????11)1()1ln ( 11?????? ????? xnxxnnn?nxnx nnnnnn)()1()()1( 11311?????? ???????????? ????????131.nnnnnxnx 11 ??? x例 5 處展開成泰勒級(jí)數(shù)在將 14 1)( ???? xxxxf解 ).1()1( )( nfx 并求的冪級(jí)數(shù)展開成 ?)1(3141???? xx?,)311(31??? x])3 1()3 1(3 11[31 2 ?? ????????? nxxx31 ??xxxxx??????41)1(41?? ?????????? nnxxxx 3 )1(3 )1(3 )1()1(31 332231 ??x!)
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