高中數(shù)學(xué)導(dǎo)數(shù)與微分教學(xué)課件-wenkub
2023-05-22 21:38:12 本頁(yè)面
【正文】 ln)21????????????（導(dǎo)數(shù)與微分 222)1(2)1(11)1()1)(1()1()1(11113????????????????????????xxxxxxxxxxxyxxy）（）（導(dǎo)數(shù)與微分 !)1()()2)(1(0)0()0()()()()()()(y),()2)(1()(,2!)1()()2)(1(0)()2)(1(lim0)0()(lim)0(1)0(),()2)(1()4(00nnfyxfxxfxfxxfxyxxfnxxxxfnnxnxxxxxfxfyynxxxxynnxx??????????????????????????????????????????????????則：令解法：利用導(dǎo)數(shù)的定義計(jì)算解法求導(dǎo)數(shù)與微分 。有些方程，可以從中解出 y，將 y表示成 x的顯函數(shù)的形式。即函數(shù)的導(dǎo)數(shù)等于函數(shù)對(duì)于函數(shù) )(,)(),( xfdxdydxxfdyxfy ??????xxxxxxxxeeydxeeedeeddyey????????????11)1(11)1l n ()1l n ()1(11 數(shù)求下列函數(shù)的微分和導(dǎo)例導(dǎo)數(shù)與微分 )s i nc os()s i nc os(c osc os)(s i ns i ns i ns i ns i n)2(bxabxbeydxbxabxbebx dxbdxas i m bxbx dbxeaxdebxbxdedebxbxdedybxeyaxaxaxaxaxaxaxaxaxaxee????????????????????????????導(dǎo)數(shù)與微分 222222122221212222221111)1()1(11)1(11)1(11)1l n ()1l n ()3(22xyxdxxxxdxxxxxdxxxxddxxxxddxxxdxxxxddyxxyxx d xx??????????????????????????????????????導(dǎo)數(shù)與微分 ? 例 12 求下列隱函數(shù)的微分和導(dǎo)數(shù) yxyyxydxyxyyxdydxyxdyyxyy dyx dyy dxx dxdyydydx ydxyxyxddyyxyxy232232)2()23(223)(1)222222223223???????????????????????????（導(dǎo)數(shù)與微分 yxyxyxyxyxyxyxyxyxexyeydxexyedydxyedyexyxdex dyy dxdeydey????????????????????????)()()(xx2)（導(dǎo)數(shù)與微分 )1()1()1()1()()(000lnx0lnx3)112?????????????????????????xyxyxyydxxyxyxydydxydyxdx dyy dxdx dyy dxdydyxyyx d yy d xxyyxxyyxyx（導(dǎo)數(shù)與微分 ? 近似計(jì)算公式????????????????xxfxfxxfxxfxfxxfy)()()()()()(000000導(dǎo)數(shù)與微分 4214|111)1()1()(,1,)():13120????????????????????????xxar c t gxfffar c t gxxar c t gxxfar c t g取設(shè)（求下列函數(shù)的近似值例導(dǎo)數(shù)與微分 應(yīng)取弧度值。注：微分公式可以與求dxxxddxxxddxxdar c c t gxdxxdar
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