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等差數(shù)列知識(shí)點(diǎn)基礎(chǔ)練習(xí)題-在線瀏覽

2024-10-23 23:52本頁(yè)面
  

【正文】 前n項(xiàng)的和,*S奇=a1+a3+a5++a2n1=n(a1+a2n1)=nan2n(a2+a2n)S偶=a2+a4+a6++a2n==nan+12S偶S奇=nan+1nan=n(an+1an)S奇nana==n S偶nan+1an+1當(dāng)項(xiàng)數(shù)為奇數(shù)2n+1時(shí),則236。S2n+1=S奇+S偶=(2n+1)an+1236。S奇=(n+1)an+1222。= 237。S奇S偶=an+1S偶n239。238。(其中an+1是項(xiàng)數(shù)為2n+1的等差數(shù)列的中間項(xiàng)).(8)、{bn}的前n和分別為An、Bn,且則An=f(n),Bnan(2n1)anA2n1===f(2n1).bn(2n1)bnB2n1(9)等差數(shù)列{an}的前n項(xiàng)和Sm=n,前m項(xiàng)和Sn=m,則前m+n項(xiàng)和Sm+n=(m+n)(10)求Sn的最值法一:因等差數(shù)列前n項(xiàng)是關(guān)于n的二次函數(shù),故可轉(zhuǎn)化為求二次函數(shù)的最值,但要注意數(shù)列的特殊性n206。法二:(1)“首正”的遞減等差數(shù)列中,前n項(xiàng)和的最大值是所有非負(fù)項(xiàng)之和即當(dāng)a10,d0,由237。an179。an+1163。236。0即 當(dāng)a10,d0,由237。0238。若S p = S q則其對(duì)稱軸為n=p+q 2注意:解決等差數(shù)列問(wèn)題時(shí),通常考慮兩類方法:①基本量法:即運(yùn)用條件轉(zhuǎn)化為關(guān)于a1和d的方程;②巧妙運(yùn)用等差數(shù)列的性質(zhì),一般地運(yùn)用性質(zhì)可以化繁為簡(jiǎn),減少運(yùn)算量.等差數(shù)列在等差數(shù)列{an}中,a4+a7+a10+a13=20,則S16= ______。已知等差數(shù)列 110,116,122,??,則大于450而不大于602的各項(xiàng)之和為 ______。的兩個(gè)根,則15若公差,且=________。N*,且m60}中元素的個(gè)數(shù),并求這些元素的和2an}{S=5n+3n,求它的前3項(xiàng),{an}的前4項(xiàng)的和是2,前9項(xiàng)的和是6,求其前n項(xiàng)和的公式?;A(chǔ)練習(xí)題一、填空題,5,2,…=12, a6=27,則d=___________ =1,a7=8,則a1=_______________ 34.(a+b)2與(ab),6,2,2,…前___項(xiàng)的和是54 {an}的前n項(xiàng)和Sn=3nn2,則an=___________二、選擇題,lg(2x1),lg(2x+3)成等差數(shù)列,則x的值等于(){an}中a3+a11=40,則a4a5+a6+a7+a8a9+a10的值為(). {an}中,前15項(xiàng)的和S15=90,a8為(){an}中, a1+a2+a3=24,a18+a19+a20=78,則此數(shù)列前20下昂的和等于 {an}中,若a3+a4+a5+a6+a7=450,則a2+a8的值等于() {an}的前n項(xiàng)的和,且Sn=n2,則{an}是(),但不是等差數(shù)列,但不是等比數(shù)列,且是等比數(shù)列 ,7,13,21,31,…的通項(xiàng)公式是()=4n=n3n2+n+=n+n+1 2三、計(jì)算題={m|m=2n1,n206。,求相應(yīng)的等差數(shù)列{an}的有關(guān)未知數(shù):(1)a1=51,d=,Sn=5,求n 及an;(2)d=2,n=15,an=10,求a1及Sn 66數(shù)列練習(xí)題在等差數(shù)列(1)若(3)若(5)若(6)若,則中,則,則=__ 2)=______(4)若,則,則=_=________=________。(7)若(8)若公差________。的兩個(gè)根,則=,則中,則=________。==81,則是方程=________。且,是由正數(shù)組成的等比數(shù)列,公比=________。=_______等差數(shù)列98,95,92,…,101-3,…,當(dāng)為何值時(shí),前項(xiàng)和最大?已知(A)能確定。設(shè)等差數(shù)列,幾項(xiàng)? 為各項(xiàng)都大于0的等比數(shù)列,公比;(B);(C),則:;(D)不中,若,求自然數(shù)的取的公差與等比數(shù)列,(1)求的公比都是,是否是,且,和的值。已知數(shù)列的通項(xiàng)公式若試求已知數(shù)列1已知求,記的整數(shù)部分為,求前n項(xiàng)的和。的前項(xiàng)和的公式為,(1)中,有,求,求數(shù)列;(2)的前項(xiàng)和,求,試用表示1對(duì)于數(shù)列1設(shè)數(shù)列求通項(xiàng)公式 的每一項(xiàng)都不為零。一個(gè)遞增(后項(xiàng)比前項(xiàng)大)的等差數(shù)列,第53 項(xiàng)比第28 項(xiàng)________(多或少)______個(gè)公差。一個(gè)遞增(后項(xiàng)比前項(xiàng)大)的等差數(shù)列,第55 項(xiàng)比第83 項(xiàng)________(多或少)______個(gè)公差。一個(gè)遞增(后項(xiàng)比前項(xiàng)大)的等差數(shù)列,第90項(xiàng)比第73項(xiàng)________(多或少)______個(gè)公差。一個(gè)遞增(后項(xiàng)比前項(xiàng)大)的等差數(shù)列,第87 項(xiàng)比首項(xiàng)________(多或少)______個(gè)公差。一個(gè)遞減(后項(xiàng)比前項(xiàng)小)的等差數(shù)列,第32項(xiàng)比第 18 項(xiàng)________(多或少)______個(gè)公差。1一個(gè)遞減(后項(xiàng)比前項(xiàng)小)的等差數(shù)列,第74項(xiàng)比第91 項(xiàng)________(多或少)______個(gè)公差。1一個(gè)遞減(后項(xiàng)比前項(xiàng)小)的等差數(shù)列,第123 項(xiàng)比第86項(xiàng)________(多或少)______個(gè)公差。1一個(gè)遞減(后項(xiàng)比前項(xiàng)小)的等差數(shù)列,第76項(xiàng)比首項(xiàng)________(多或少)______個(gè)公差。1一個(gè)遞增(后項(xiàng)比前項(xiàng)大)的等差數(shù)列,第________項(xiàng)比第75項(xiàng)少19 個(gè)公差。一個(gè)遞增(后項(xiàng)比前項(xiàng)大)的等差數(shù)列,比第92 項(xiàng)少 19 個(gè)公差是第________項(xiàng)。2一個(gè)遞增(后項(xiàng)比前項(xiàng)大)的等差數(shù)列,比首項(xiàng)多19個(gè)公差是第________項(xiàng)。2一個(gè)遞減(后項(xiàng)比前項(xiàng)小)的等差數(shù)列,第________項(xiàng)比第58
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