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精益生產(chǎn)之采購件拉系統(tǒng)案例分析purchasedpartspull-在線瀏覽

2025-02-19 22:07本頁面
  

【正文】 CAGR) 高于行業(yè)平均增長速度,產(chǎn)品在位于達拉斯市的一個小工廠生產(chǎn)。 11 Purchased Parts Pull System – Case Study Improve Replenishment Pull Case Study (Cont.) During John‘s assessment of the raw glass procurement process, he conducted interviews and uncovered the following information. ? From the Master Scheduler: ? MRP generates all orders and action messages for raw material once per week ? Schedule changes are mon and probably drives excessive messages ? Safety stock is not used but excess inventory exists due to the large number of schedule changes. ? From the Raw Material Commodity Buyer: ? Only 15 unique raw glass part numbers ? Lead time for the glass is 1 week (regardless of mix) and the supplier is very dependable ? Glass supplier runs the glass for the window pany about once per quarter ? Glass supplier has minimum shipment requirement of one truckload (20 containers 300 per container) ? Containers are 439。 and can be stacked 3 high ? Various order frequency used to order raw glass (no real strategy) 12 Purchased Parts Pull System – Case Study Improve 補充拉系統(tǒng)案例 約翰在評價玻璃原材料的采購過程時,訪問了一些部門并得到以下信息: ? 從主計劃 : ? MRP每周一次生成有關(guān)原材料的所有訂貨和行動信息 ? 計劃變更很平常,可能產(chǎn)生額外的信息 ? 安全庫存未使用,但過剩的在制存貨由于大量的計劃變更而存在。 15 Purchased Parts Pull System – Case Study Improve Exhibit 1 P a r tA D U ( U ni t s / D a y ) C urr e nt O r de r Fre qu e nc y ( D a y s )Le a d Ti m e ( D a y s ) S t d C os tC urr e nt O n H a nd $ 39。 sA 1 , 6 0 0 10 5 5 . 0 0$ 9 6 , 0 0 0$ B 3 , 0 0 0 10 5 8 . 0 0$ 2 8 8 , 0 0 0$ C 700 10 5 1 . 7 5$ 1 4 , 7 0 0$ D 1 , 2 0 0 10 5 2 4 . 0 0$ 3 4 5 , 6 0 0$ E 1 , 0 0 0 5 5 3 5 . 0 0$ 2 1 0 , 0 0 0$ F 2 , 0 0 0 5 5 2 . 0 0$ 2 4 , 0 0 0$ G 150 10 5 8 . 0 0$ 1 4 , 4 0 0$ H 200 5 5 4 . 0 0$ 4 , 8 0 0$ I 110 20 5 9 . 0 0$ 2 3 , 7 6 0$ J 800 20 5 4 . 0 0$ 7 6 , 8 0 0$ K 8 , 5 0 0 10 5 2 8 . 0 0$ 2 , 8 5 6 , 0 0 0$ L 170 20 5 6 . 0 0$ 2 4 , 4 8 0$ M 4 , 3 0 0 10 5 3 5 . 0 0$ 1 , 8 0 6 , 0 0 0$ N 2 , 5 0 0 10 5 3 4 . 0 0$ 1 , 0 2 0 , 0 0 0$ O 1 , 5 0 0 5 5 1 . 2 5$ 1 1 , 2 5 0$ 2 7 , 7 3 0 6 , 8 1 5 , 7 9 0$ ADU=平均日用量 17 Purchased Parts Pull System – Case Study Improve Exhibit 2 P a r t ADUS t d C o s tABC C o d eS t a n d a r d D e v i a t i o n ( l a s t 1 2 m o n t h s )S / X ( l a s t 1 2 m o n t h s )K 8 , 5 0 0 2 8 . 0 0$ A 1000 0 . 1 3 M 4 , 3 0 0 3 5 . 0 0$ A 9500 2 . 3 0 N 2 , 5 0 0 3 4 . 0 0$ B 1200 0 . 7 0 E 1 , 0 0 0 3 5 . 0 0$ B 900 1 . 1 0 D 1 , 2 0 0 2 4 . 0 0$ B 3500 3 . 0 0 B 3 , 0 0 0 8 . 0 0$ C 1400 0 . 4 0 A 1 , 6 0 0 5 . 0 0$ C 300 0 . 2 0 F 2 , 0 0 0 2 . 0 0$ C 1500 0 . 8 5 J 800 4 . 0 0$ C 125 0 . 1 5 O 1 , 5 0 0 1 . 2 5$ C 1400 1 . 2 0 C 700 1 . 7 5$ C 150 0 . 2 0 G 150 8 . 0 0$ C 120 1 . 1 0 L 170 6 . 0 0$ C 250 1 . 5 0 I 110 9 . 0 0$ C 500 4 . 7 0 H 200 4 . 0 0$ C 250 1 . 3 0 2 7 , 7 3 0 18 Purchased Parts Pull System – Case Study Improve 表 2 零件 ADU 標準成本ABC 編碼標準差( 最近個 12 月 )S / X( 最近 12個月 )K 8 , 5 0 0 2 8 . 0 0$
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