【摘要】1.已知:AB=4,AC=2,D是BC中點(diǎn),AD是整數(shù),求ADADBC解:延長(zhǎng)AD到E,使AD=DE∵D是BC中點(diǎn)∴BD=DC在△ACD和△BDE中AD=DE∠BDE=∠ADCBD=DC∴△ACD≌△BDE∴AC=BE=2∵在△ABE中AB-BE<AE<AB+BE∵AB=4即4-2<2AD<4+21<AD<3
2025-06-27 18:26
【摘要】1.已知:AB=4,AC=2,D是BC中點(diǎn),AD是整數(shù),求ADADBC解:延長(zhǎng)AD到E,使AD=DE∵D是BC中點(diǎn)∴BD=DC在△ACD和△BDE中AD=DE∠BDE=∠ADCBD=DC∴△ACD≌△BDE∴AC=BE=2∵在△ABE中AB-BE<AE<AB+BE∵AB=4即4-2<2AD<4+21<AD<3∴AD=22.已知:D是AB中點(diǎn),∠A
2025-06-22 22:49
【摘要】第一篇:全等三角形證明經(jīng)典50題(含答案) 全等三角形證明經(jīng)典50題(含答案) :AB=4,AC=2,D是BC中點(diǎn),AD是整數(shù),求AD B D :D是AB中點(diǎn),∠ACB=90°,求證:CD=...
2024-11-05 12:09
【摘要】第一篇:全等三角形證明經(jīng)典50題(含答案)_ 全等三角形證明經(jīng)典50題(含答案) :D是AB中點(diǎn),∠ACB=90°,求證:CD= 1AB 2延長(zhǎng)CD與P,使D為CP中點(diǎn)。連接AP,BP ∵D...
【摘要】全等三角形證明證明經(jīng)典50題1.已知:AB=4,AC=2,D是BC中點(diǎn),AD是整數(shù),求ADADBC2.已知:D是AB中點(diǎn),∠ACB=90°,求證:DABC3.已知:BC=DE,∠B=∠E,∠C=∠D,F(xiàn)是CD中點(diǎn),求證:∠1=∠2ABCDEF214.已知:∠1=∠2,CD=DE,EF
2025-06-10 15:37
【摘要】全等三角形證明經(jīng)典50題(含答案)1.已知:AB=4,AC=2,D是BC中點(diǎn),AD是整數(shù),求ADADBC解:延長(zhǎng)AD到E,使AD=DE∵D是BC中點(diǎn)∴BD=DC在△ACD和△BDE中AD=DE∠BDE=∠ADCBD=DC∴△ACD≌△BDE∴AC=BE=2∵在△ABE中AB-BE<AE<AB+BE∵AB=4即
2025-06-22 22:55
2025-06-22 22:58
2025-06-22 23:06
【摘要】全等三角形證明經(jīng)典題(含答案)1.已知:AB=4,AC=2,D是BC中點(diǎn),111749AD是整數(shù),求ADADBC解:延長(zhǎng)AD到E,使AD=DE∵D是BC中點(diǎn)∴BD=DC在△ACD和△BDE中AD=DE∠BDE=∠ADCBD=DC∴△ACD≌△BDE∴AC=BE=2∵在△ABE中AB-BE<AE<AB+BE∵AB=4
【摘要】....全等三角形證明經(jīng)典題(含答案)1.已知:AB=4,AC=2,D是BC中點(diǎn),111749AD是整數(shù),求ADADBC解:延長(zhǎng)AD到E,使AD=DE∵D是BC中點(diǎn)∴BD=DC在△ACD和△BDE中AD=DE∠BDE=∠ADCB
2025-06-22 23:08
【摘要】已知:AB=4,AC=2,D是BC中點(diǎn),AD是整數(shù),求ADADBC已知:D是AB中點(diǎn),∠ACB=90°,求證:DABCBACDF21E已知:∠1=∠2,CD=DE,EF//AB,求證:EF=ACA1.已知:AD平分∠BAC,AC=AB+BD,求證:
【摘要】2016專題:《全等三角形證明》1.已知:D是AB中點(diǎn),∠ACB=90°,求證:DABC2.已知:BC=DE,∠B=∠E,∠C=∠D,F(xiàn)是CD中點(diǎn),求證:∠1=∠2ABCDEF213.已知:AC平分∠BAD,CE⊥AB,∠B+∠D=180°,求證:AE=AD+BE4.如圖,四邊形ABCD中
2025-03-27 07:41
【摘要】第一篇:全等三角形證明經(jīng)典10題((含答案) 全等三角形證明經(jīng)典10題(含答案)如圖,已知:AD是BC上的中線,且DF=DE.求證:BE∥CF. ,在ΔABC中,D是邊BC上一點(diǎn),AD平分∠BAC...
2024-08-06 08:58
【摘要】第一篇:全等三角形證明經(jīng)典50題[范文模版] :AB=4,AC=2,D是BC中點(diǎn),AD是整數(shù),求AD BD :D是AB中點(diǎn),∠ACB=90°,求證:CD= 12AB :BC=DE,∠B=∠E...
2024-10-23 07:37