雙原子分子初級(jí)ppt課件(參考版)
2025-05-09 18:02本頁(yè)面
【正文】 , so such a cation might be predicted to exist. The electron configuration for this cation is: [He2]+ = 1?g21?u*1 Diatomic molecules: Homonuclear Molecules of the Second Period The bond order in Li2 is (42)/2 = 1, so the molecule could exists. In fact, a bond energy of 105 kJ/mol has been measured for this molecule. Li Energy Li Li2 1s 1s 1?g 1?*u 2s 2s 2?g 2?*u The bond order in Be2 is (44)/2 = 0, so the molecule can not exist as a covalently bounded molecule. Be Energy Be Be2 1s 1s 1?g 1?*u 2s 2s 2?g 2?*u Diatomic molecules: Homonuclear Molecules of the Second Period This produces an MO over the molecule with a node between the F atoms. This is thus an antibonding MO of ?*u symmetry. Diatomic molecules: The bonding in F2 2pzA + 2pzB The binations of ? symmetry: This produces an MO around both F atoms and has the same phase everywhere and is symmetrical about the FF axis. This is thus a bonding MO of ?g symmetry. 2pzA 2pzB 3?g 3?*u This produces an MO over the molecule with a node on the bond between the F atoms. This is thus a bonding MO of ?u symmetry. Diatomic molecules: The bonding in F2 2pyA + 2pyB The first set of binations of ? symmetry: 1?u This produces an MO around both F atoms that has two nodes: one on the bond axis and one perpendicular to the bond. This is thus an antibonding MO of ?*g symmetry. 2pyA 2pyB 1?*g F Energy F F2 2s 2s 1?g 1?*u 2p 2p 2?g 2?*u 1?u 1?*g (px,py) pz O2: KK(?2s)2 (?*2s)2 (? 2p)2 (?2p)4 (?*2p)2 F2: KK(?2s)2 (?*2s)2 (?2p)2 (?2p)4
教學(xué)課件相關(guān)推薦
鄂ICP備17016276號(hào)-1