【正文】 an, the starting point of the ancient Silk Road, a trade channel established more than 2,000 years ago linking China, Central Asia and Europe.。s cooperation with Central Asian countries, a senior official said. Shaanxi Governor Lou Qinjian said the province is fresh, rich and unique, as it was when it anchored one end of the ancient Silk Road. It is the best option for acmodating industrial transfers from East China or the world at large, he said on Wednesday in Xi39。s business development. Rudy Buttignol, president of the public broadcasting pany in British Columbia, Canada, said his work requires frequent travel to Chengdu and the policy makes the trips easier. Data from the city39。s largest breeding and research center. Three days are long enough for foreign visitors to visit those iconic tourist spots, he noted. The city is home to the remains of the Jin sha civilization that dates back more than 3,000 years as well as the Qing cheng Mountains and the Du jiang yan irrigation system. Qing cheng has long been recognized as the birthplace of Taoism, China39。s 72hour visafree policy has attracted wide attention from both Chinese and foreign experts and businessmen since it took effect on Sept 1 last year. The program permits citizens from 51 countries and regions including the United States, Australia, Canada and Japan who have valid visas and flight tickets to a third country to spend three days in the city. The capital of Sichuan province is the first city in the western region of China to offer foreign tourists a threeday visa and the fourth nationwide to adopt the policy following Shanghai, Beijing and Guangzhou. Li Zhiyong, deputy dean of the tourism institute at Sichuan University, said the move contributes to a large increase in the number of overseas tourists and raises the city39。output_File_Words 星期 week+1 的 hour+8 點的數(shù)據(jù)為：endl 當窗口個數(shù)為 windows 時： endl 得到服務的顧客數(shù)為 Count_Ls endl 得到服務的顧客所需要的平均等待時間為 averageWaitTime endl 隊列平均長度為 sum_Ls/Count_Ls endl endl。if(sum_Ls) averageWaitTime= ( totalServiceTimeSum_Wait_Time )/Count_Ls。 windowTime[Count] = finishService。 (finishService)。 Sum_Wait_Time+=rand_service_time。 rnd2 = ((double)rand())/RAND_MAX。 (windowTime[Count] lastTime) ) { customer = ()。 !() amp。++Count) { if ( (windowTime[Count] = t) amp。 } for(Count = 0。 (t)。()=M) { sum_Ls+=()。 if ((rnd1= customers_Arrived_Per_Time)amp。 t lastTime。double Sum_Wait_Time=0。double sum_Ls=。 Count windows。 int Count = 0。double rnd1。 double totalServiceTime = 0。 output_File_Numbers,int week,int hour){Customer customer。}void function(int windows, double customers_Arrived_Per_Time, double customers_Served_Per_Time, double lastTime,ofstreamamp。 } }system(pause)。 customers_Served_Per_Time=60*mu[i][j]。 windows = MAX_WINDOWS。j10。i7。cout endl。cout 請輸入仿真持續(xù)的時間（單位：分）: 。coutmu[i][j]endl。j10。i7。coutlanda[i][j]endl。j10。i7。srand(time(NULL))。()。ofstream output_File_Numbers。ifstream input_File。double landa[7][10]={0}。double customers_Served_Per_Time。int main(){double y=0。 output_File_Words,ofstreamamp。const int MAX_WINDOWS = 10。 return 0。iM。 cout評價指標z=z[i]endl。} cout窗口數(shù)n=index endl。i++) if(tempd[i]) {temp=d[i]。 if(flag==0) { for(i=1。 } j++。 cout評價指標z=z[i]endl。(temp=cs*(i+1)+cw*ls[i+1])) { cout窗口數(shù)n=i endl。 if((temp=(cs*(i1)+cw*ls[i1]))amp。iM) { d[j]=c[i]。i0amp。 if((z[i]=(t*PERCENT+min))amp。i++) { c[i]=cs*i+cw*ls[i]。 } for(i=0。 if(minz[i]) min=z[i]。iM。 double max=z[0],min=z[0]。 double ls[M]={ 0,}。 double temp=0。 int index=0。 int i=0。int main(){ double c[20]={0}。double cw=3。zzx{ii}=sum(sum(zzx{ii}))/65。 zzx{ii}(find(isnan(zzx{ii})))=0。 zzx{ii}=z{ii}。 zzx={}。 end celldisp(lxx)。for pp=1:1:70 for p=2:1:n lxx{pp}(p1)=lx{p}(pp)。 end celldisp(zz)。for pp=1:1:70 for p=2:1:n zz{pp}(p1)=z{p}(pp)。endcelldisp(z)。n。disp(wq(12))。disp(a(12))。z{n}=.*(1ggpm)+.*gga+.*q+.*(1ggls)+.*(1ggwq)。gwq=(wqewq)./vwq。ewq=mean(owq)。owq=reshape(wq,70,1)。gls=(lsels)./vls。els=mean(ols)。ols=reshape(ls,70,1)。ga=(aea)./va。ea=mean(oa)。oa=reshape(a,70,1)。gpm=(pmepm)./vpm。epm=mean(opm)。opm=reshape(pm,70,1)。ls=lg+(r.*q)./u。q=1pm。 lg=((p1.*(n.*p1).^n)./(prod(1:n).*(1p1).^2).*(1(mn+1).*p1.^(mn)+(mn).*p1.^(mn+1)))