【正文】
方程關于解PNPMP M Nnmpmpmpnmpnxxmpx????????????????341:4144414,444)(4)(22,)1(144),1,2()2(22212122122121221212????????????????????????????????xxyaaaaaxxxxMNxxxxxxxxxxMNPQMNM P Caaxaxy拋物線的解析式為解得而又如圖示為等腰直角三角形知又由代入解析式中得拋物線的頂點為兩點相交于與拋物線坐標為圓心則如圖示軸的直線為設平行于BAxxykykokyx,34),2(,)3(2,??????342 ????xxyky? 一定有兩個不相等的實數(shù)根 1:0)3(4)4(03434222?????????????????kkkxxkxx求得數(shù)根一定有兩個不相等的實即方程)251,2(39。1251:01:4)3(443,40344)(4222221212212212122?????????????????????????????的坐標為圓心求得化簡得中在方程而即軸相切好與為直徑的圓恰以OkkkkkkxxxxkxxxxxxxxABkABkABxA