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單片機(jī)原理與運(yùn)用-第三章答案-資料下載頁(yè)

2025-06-27 13:49本頁(yè)面
  

【正文】 A 。源地址數(shù)據(jù)與目標(biāo)地址數(shù)據(jù)交換INC R0 。源地址指針修正INC R1 。目標(biāo)地址指針修正DJNZ R6,LOOP 。計(jì)數(shù)長(zhǎng)度減1,不等于0繼續(xù)循環(huán)RET END24試編寫一程序,將存儲(chǔ)區(qū)DATA1單元開始的50個(gè)單字節(jié)逐一移至DATA2單元開始的存儲(chǔ)區(qū)中。解:START:MOV R0,DATA1 。建立源操作數(shù)地址指針 MOV R1,DATA2 。建立目標(biāo)操作數(shù)地址指針MOV R6,50 。置計(jì)數(shù)長(zhǎng)度LOOP: MOV A,@R0 MOV @R0,A INC R0 INC R1 DJNZ R6,LOOP RET END25試編寫一采用查表法求1~20的平方數(shù)子程序(要求:x在累加器A中,1≤x≤20,平方數(shù)高位存放在R6,低位在R7)解:為了方便起見,每一數(shù)的平方在表中統(tǒng)一用雙字節(jié)來(lái)存放,這樣只要把數(shù)乘以2加表頭地址,就可以找到平方數(shù)的高字節(jié)存放的地址,連續(xù)取兩個(gè)字節(jié)即可 ORG 0000HSJMP STARTORG 0030HSTART: MOV DPTR,TAB 。建立源地址指針DEC AMOV B,AADD A,BMOV B,ALOOP: MOVC A,@A+DPTRMOV R5,AINC DPTRMOV A,BMOVC A,@A+DPTRMOV R6,ARET TAB: DB00H,00H,00H,01H,00H,04H,00H,09H,00H,16H。平方數(shù)用BCD表示(也可用DB 00H,25H,00H,36H,00H,49H,00H,64H,00H,81H。十六進(jìn)制表示)DB 01H,00H,01H,21H,01H,44H,01H,69H,01H,96HDB 02H,25H,02H,56H,02H,89H,03H,24H,03H,61H,04H,00HEND 若平方表從0的平方存放,把程序中紅色的DEC A指令去掉,若表從1的平方存放,則將DEC A指令加上。26試編寫一個(gè)三字節(jié)無(wú)符號(hào)數(shù)乘法程序。解: OGR 0000H MOV R0,5CHMUL1: MOV A,5AH MOV B58H MUL ABMOV @R0,A MOV R3,B MOV A,5BH MOV B,5BH MUL AB ADD A,R3 MOV R3,A MOV A,BADD A,R2MOV R2,AMOV R1,AJNC LASTINC R1LAST: MOV A,5BH MOV B,29H MUL AB ADD A,R2 INC R0 MOV @R0,A MOV A,B ADDC A,RI INC R0 MOV @R0,A MOV R5,04HMOV R1,10HLOOP: MOV A,@R0 MOV @R1,A INC R0INC R1 BINBCD: MOV R1,48H MOV R2,04H INC R2 CLR A BB0: MOV @R1,A INC R1 DJNZ R2,BB0 MOV A,04H MOV B,8 MUL AB MOV R3,ABB3: MOV R0,10H MOV R2,04H CLR CBB1: MOV A,@R0 RLC A MOV @R0,A INC R0 DJNZ R2,BB1 MOV R2,04HINC R2MOV R1,48HBB2: MOV A,@R1 ADDC A,@R1 DA A MOV @R1,A INC R1 DJZN R2,BB2 DJZN R3,BB3 SJMP $
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