高一物理牛頓運(yùn)動定律綜合測試題試卷及參考答案-資料下載頁
2025-06-07 23:18本頁面
【正文】 （4）________1_______kg13.（1）作出假設(shè)、搜集證據(jù). （2）_______勻速________運(yùn)動，. （3）加速度減小的加速_運(yùn)動，_______勻速_______運(yùn)動. （4）圖線1:勻速運(yùn)動。圖線5:. 加速度減小的加速運(yùn)動三、本題共小題，共40分，解答應(yīng)寫出必要的文字說明、方程式和重要演算步驟。只寫出最后答案的不能得分。 有數(shù)值計算的題，答案中必須明確寫出數(shù)值和單位。FGθ14: F tanθ = ma a = gtanθ物體向右做勻加速；物體向左做勻減速GGGFN15．Μmg = ma a = μg = 1m/s2 t1 = v/a =1sx1 = at2/2 = 2m x2 = x—x1=20m—2m=18mt2 = x2/v = 9st = t1+t2 = 11sABvFfFGFfFN16：Fcosθ—μFN = 0 FN + Fsinθ—mg = 0μ = 1/3 a = μg = 10/3 m/s2x = 15mFTG1Ff1FNAG1+G2FFTFNBFf217:BAθFFTcosθ—μFNA = 0FNA + FTsinθ—G1 = 0 FT = F — μFNB — FTcosθ=0FTsinθ + FNB — G1 — G2 = 0 F = 18.CθABkx1 = mAgsinθkx2 = mBgsinθF— kx2 — mAgsinθ = mAaa = (F— mAgsinθ— mBgsinθ)/mAd = x1 + x2 = (mA + mB)gsinθ/k
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