【總結(jié)】對(duì)數(shù)函數(shù)單調(diào)性練習(xí)一、填空題=loga(3-ax)在[0,2)上是關(guān)于x的減函數(shù),則實(shí)數(shù)a的取值范圍為(x)=log2(x2-ax-4)在區(qū)間[2,4]上是增函數(shù),則實(shí)數(shù)a的范圍是=log2(x2-ax-a)定義域?yàn)镽,則實(shí)數(shù)a的取值范圍是(x)=loga(ax2-x+3)在[2,4]上是增函數(shù),則實(shí)數(shù)a的取值范圍是
2025-06-24 15:04
【總結(jié)】下午4時(shí)31分53秒.1對(duì)數(shù)下午4時(shí)31分53秒思考問(wèn)題一:某個(gè)同學(xué)拿出一張紙,進(jìn)行對(duì)折折紙次數(shù)和層數(shù)有什么關(guān)系?下午4時(shí)31分53秒折紙次數(shù)x層數(shù)N2xN?折紙次數(shù)和層數(shù)的關(guān)系:思考問(wèn)題一:如果我已經(jīng)知道一共有128層,你能計(jì)算折了多少次嗎?
2025-01-06 16:32
【總結(jié)】?2020NENU濟(jì)南九中高三數(shù)學(xué)備課組?2020NENU濟(jì)南九中高三數(shù)學(xué)備課組考試說(shuō)明①理解對(duì)數(shù)的概念及其運(yùn)算性質(zhì);知道用換底公式能將一般對(duì)數(shù)轉(zhuǎn)化成自然對(duì)數(shù)或常用對(duì)數(shù);了解對(duì)數(shù)在簡(jiǎn)化運(yùn)算
2025-10-31 08:48
【總結(jié)】ab=N→logaN=b對(duì)數(shù)的概念ab=N→logaN=bab=N→logaN=b引子:例2020年我國(guó)國(guó)民生產(chǎn)總值為a億元,如果每年平均增長(zhǎng)8%,那么經(jīng)過(guò)多少年國(guó)民生產(chǎn)總值是2020年的2倍?抽象出:這是已知底數(shù)和冪的值,求指數(shù)!你能看得出來(lái)嗎?怎樣求呢?數(shù)2(底),4(指數(shù))
2025-10-28 18:57
【總結(jié)】第八節(jié)對(duì)數(shù)與對(duì)數(shù)函數(shù)基礎(chǔ)梳理1.對(duì)數(shù)及對(duì)數(shù)的運(yùn)算(1)定義:ab=N?b=________(a0,且a≠1).(2)積、商、冪、方根的的對(duì)數(shù)(M、N都是正數(shù),a0,且a≠1,n0)①loga(MN)=_______________.②=____
2025-10-31 01:25
【總結(jié)】第七節(jié)對(duì)數(shù)與對(duì)數(shù)函數(shù)(1)定義:一般地,如果,那么x叫做,記作,其中a叫做對(duì)數(shù)的,N叫做.(2)對(duì)數(shù)性質(zhì)①
2025-11-02 08:49
【總結(jié)】2022屆高考數(shù)學(xué)復(fù)習(xí)強(qiáng)化雙基系列課件10《對(duì)數(shù)和對(duì)數(shù)函數(shù)》考試說(shuō)明①理解對(duì)數(shù)的概念及其運(yùn)算性質(zhì);知道用換底公式能將一般對(duì)數(shù)轉(zhuǎn)化成自然對(duì)數(shù)或常用對(duì)數(shù);了解對(duì)數(shù)在簡(jiǎn)化運(yùn)算中的作用.;樂(lè)動(dòng)體育LD樂(lè)動(dòng)
2025-07-25 15:40
【總結(jié)】范文范例參考課題:對(duì)數(shù)函數(shù)考綱要求:掌握對(duì)數(shù)函數(shù)的概念、圖象和性質(zhì);能利用對(duì)數(shù)函數(shù)的性質(zhì)解題.教材復(fù)習(xí)一般地,我們把函數(shù)叫做對(duì)數(shù)函數(shù),其中是自變量,函數(shù)的定義域是對(duì)數(shù)函數(shù)的圖象與性質(zhì):圖象定義域值域性質(zhì)過(guò)定點(diǎn)(,)
2025-04-17 00:38
【總結(jié)】(1)對(duì)數(shù)的定義①若,則叫做以為底的對(duì)數(shù),記作,其中叫做底數(shù),叫做真數(shù).②負(fù)數(shù)和零沒(méi)有對(duì)數(shù).③對(duì)數(shù)式與指數(shù)式的互化:.(2)幾個(gè)重要的對(duì)數(shù)恒等式,,.(3)常用對(duì)數(shù)與自然對(duì)數(shù)常用對(duì)數(shù):,即;自然對(duì)數(shù):,即(其中…).(4)對(duì)數(shù)的運(yùn)算性質(zhì)如果,那么①加法:②減法:③數(shù)乘:④⑤⑥換底公式:
2025-05-16 03:53
【總結(jié)】 對(duì)數(shù)函數(shù)及其性質(zhì)1.對(duì)數(shù)函數(shù)的概念(1)定義:一般地,我們把函數(shù)y=logax(a>0,且a≠1)叫做對(duì)數(shù)函數(shù),其中x是自變量,函數(shù)的定義域是(0,+∞).(2)對(duì)數(shù)函數(shù)的特征:特征判斷一個(gè)函數(shù)是否為對(duì)數(shù)函數(shù),只需看此函數(shù)是否具備了對(duì)數(shù)函數(shù)的特征.比如函數(shù)y=log7x是對(duì)數(shù)函數(shù),而函數(shù)y=-3log4x和y=logx2均不是對(duì)數(shù)函數(shù),其原因是不符合對(duì)數(shù)函數(shù)
2025-05-16 07:56
【總結(jié)】《對(duì)數(shù)函數(shù)》教學(xué)課案一、教材分析本節(jié)課是新課標(biāo)高中數(shù)學(xué)必修①中第三章對(duì)數(shù)函數(shù)內(nèi)容的第二課時(shí),,,在高考中占有一定的分量,它是在指數(shù)函數(shù)的基礎(chǔ)上,對(duì)函數(shù)類型的拓廣,,可以讓學(xué)生理解對(duì)數(shù)函的概念,從而進(jìn)一步深化對(duì)對(duì)數(shù)模型的認(rèn)識(shí)與理解。同時(shí),通過(guò)對(duì)數(shù)概念的學(xué)習(xí),對(duì)培養(yǎng)學(xué)生對(duì)立統(tǒng)一,相互聯(lián)系、相互轉(zhuǎn)化的思想,培養(yǎng)學(xué)生的邏輯思維能力都具有重要的意義.二、學(xué)情分析大部分學(xué)生學(xué)習(xí)的自主
2025-08-05 04:43
【總結(jié)】[小題熱身]1.函數(shù)y=xln(1-x)的定義域?yàn)?)A.(0,1)B.[0,1)C.(0,1]D.[0,1]解析:由題意,得?????x≥0,1-x0,解得0≤x1,故函數(shù)y=xln(1-
2025-08-05 05:42
【總結(jié)】對(duì)數(shù)函數(shù)提高精講【基礎(chǔ)】1.對(duì)數(shù)的運(yùn)算法則(a0,且a≠1,M0,N0)①loga(M·N)=logaM+logaN;②loga=logaM-logaN;③logaMn=nlogaM(n∈R);④loga=logaM.幾個(gè)恒等式(M,N,a,b都是正數(shù),且a,b≠1)①alogaN=N;②logaaN=N;③log
2025-04-04 04:59
【總結(jié)】指數(shù)函數(shù)、對(duì)數(shù)函數(shù)、冪函數(shù)練習(xí)題一、選擇題1.下列函數(shù)中,是冪函數(shù)的是()A.B.C.D.2.已知,則=()A.B.C.D.3.若,則()A.B.
2025-03-25 02:35
【總結(jié)】第三章 指數(shù)函數(shù)和對(duì)數(shù)函數(shù)§1 正整數(shù)指數(shù)函數(shù)§2 指數(shù)擴(kuò)充及其運(yùn)算性質(zhì)1.正整數(shù)指數(shù)函數(shù)函數(shù)y=ax(a0,a≠1,x∈N+)叫作________指數(shù)函數(shù);形如y=kax(k∈R,a0,且a≠1)的函數(shù)稱為_(kāi)_______函數(shù).2.分?jǐn)?shù)指數(shù)冪(1)分?jǐn)?shù)指數(shù)冪的定義:給定正實(shí)數(shù)a,對(duì)于任意給定的整數(shù)m,n(m,n互素),存在唯一的正實(shí)數(shù)