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[理學(xué)]2-4矩陣分塊法-展示頁(yè)

2025-01-28 14:34本頁(yè)面
  

【正文】 ???srAAA????設(shè) rA11sA.11???????????TsrTTAAA????則 TsA1TrA1TsA1TrA1.11??????????TsrTT ??則,21???????????????sAAAA?OO? ?.,2,1對(duì)角矩陣為分塊那末稱(chēng)都是方陣其中 AsiA i ??.21 sAAAA ??分塊對(duì)角矩陣的行列式具有下述性質(zhì) : ? ? 并有則若 ,0,2,10 ??? AsiA i ?.21???????????????sAAAA?oo? ? ,6 21???????????????sAAAA?設(shè)oo1?1?1?1?? ?????????????????????????????ssBBBAAA??????????????00000000000072121.0000002211???????????????ssBABABA???????例 1 (P49) 設(shè) ,1011012100100001????????????????A ,0211140110210101??????????????????B.AB求解 分塊成把 BA ,????????????????1011012100100001A???????????????10011001A00001121?,??????? EEO1A??????????????????0211140110210101B??????? 11B E21B 22B則 ?????????????2221111 BBEBEAOEAB.2212111111 ????????? BABBAEB.2212111111 ????????? BABBAEBAB又 21111 BBA ? ?????????????????????? ??110121011121??????????????? ??11012043 ,1142 ?????????????????????? ???02141121221 BA ,1333 ???????于是 ????????? 2212111111BABBAEBAB.1311334210410101??????????????????,100100000001???????????????bbaaA設(shè)?????????????bbaaB100000001000., ABABA ?求例 2 解 分塊將 BA ,???????????????bbaaA10
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