【總結(jié)】謝謝觀看Thankyouforwatching!
2025-06-14 12:05
【總結(jié)】第二章二次函數(shù)導(dǎo)入新課講授新課當(dāng)堂練習(xí)課堂小結(jié)第5課時(shí)二次函數(shù)y=ax2+bx+c的圖象與性質(zhì)二次函數(shù)的圖象和性質(zhì)情境引入學(xué)習(xí)目標(biāo)y=ax2+bx+c化成頂點(diǎn)式y(tǒng)=a(x-h)2+k.(難點(diǎn))y=ax2+bx+c的頂點(diǎn)坐標(biāo)、對(duì)稱軸.(重點(diǎn))導(dǎo)入新課復(fù)習(xí)引入
2025-06-18 01:16
【總結(jié)】第二章二次函數(shù)導(dǎo)入新課講授新課當(dāng)堂練習(xí)課堂小結(jié)第4課時(shí)二次函數(shù)y=a(x-h)2+k的圖象與性質(zhì)二次函數(shù)的圖象和性質(zhì)學(xué)習(xí)目標(biāo)y=a(x-h)2+k(a≠0)的圖象.y=a(x-h)2+k(a≠0)的圖象的性質(zhì)并會(huì)應(yīng)用.(重點(diǎn))y=a(x-h)2+k(a≠0)與y=ax2(a≠0
2025-06-18 01:43
【總結(jié)】◆知識(shí)導(dǎo)航◆典例導(dǎo)學(xué)◆反饋演練(◎第一階◎第二階◎第三階)◆知識(shí)導(dǎo)航◆典例導(dǎo)學(xué)◆反饋演練(◎第一階◎第二階◎第三階)◆知識(shí)導(dǎo)航◆典例導(dǎo)學(xué)◆反饋演練(◎第一階◎第二階◎第三階)◆知識(shí)導(dǎo)航◆典例導(dǎo)學(xué)◆反饋演練(◎
2025-06-12 08:20
2025-06-20 03:59
【總結(jié)】2 二次函數(shù)的圖象與性質(zhì)第3課時(shí)【基礎(chǔ)梳理】y=a(x-h)2的性質(zhì)其對(duì)稱軸是x=__,頂點(diǎn)坐標(biāo)是(h,0)y=a(x-h)2與y=ax2的關(guān)系它們_____相同,只是_____不同.當(dāng)h0時(shí),拋物線y=ax2向___平移h個(gè)單位,得到y(tǒng)=a(x-h)2;當(dāng)h0時(shí),拋物線y=ax2向___平移|h|
2025-06-21 02:29
【總結(jié)】2二次函數(shù)的圖象與性質(zhì)第2課時(shí)【基礎(chǔ)梳理】y=ax2(a為常數(shù),a≠0)的圖象與性質(zhì)函數(shù)y=ax2(a0)y=ax2(a0)y=ax2(a0)頂點(diǎn)坐標(biāo)_________
2025-06-12 12:32
2025-06-21 02:27
【總結(jié)】2二次函數(shù)的圖象與性質(zhì)第3課時(shí)【基礎(chǔ)梳理】y=a(x-h)2的性質(zhì)其對(duì)稱軸是x=__,頂點(diǎn)坐標(biāo)是______.h(h,0)y=a(x-h)2與y=ax2的關(guān)系它們_____相同,只是_____不同.當(dāng)h0時(shí),拋物線y=ax2向___平移h個(gè)單位,得到y(tǒng)=a(x-h)2;當(dāng)h0時(shí),拋
【總結(jié)】2二次函數(shù)的圖象與性質(zhì)第1課時(shí)【基礎(chǔ)梳理】二次函數(shù)y=x2與y=-x2的圖象與性質(zhì)函數(shù)y=x2y=-x2圖象開口方向__________向上向下函數(shù)y=x2y=-x2頂點(diǎn)坐標(biāo)______________對(duì)稱軸y軸y軸函數(shù)變化當(dāng)x&g
2025-06-12 12:36
【總結(jié)】2二次函數(shù)的圖象與性質(zhì)第4課時(shí)些數(shù)學(xué)問(wèn)題.y=ax2+bx+c的圖象特征,會(huì)用配方法求其對(duì)稱軸、頂點(diǎn)坐標(biāo)公式.、對(duì)稱軸和頂點(diǎn)坐標(biāo).(1)y=2(x-3)2-5(2)y=-(x+1)2(3)y=3(x+4)2+2移得到的?【解析】1.(1)開口:向上,對(duì)稱軸:直線x=3,頂點(diǎn)坐標(biāo)(
2025-06-15 02:53
2025-06-15 03:00