【正文】 00 BX=0000 CX=0016 DX=0000 SP=0000 BP=0000 SI=0000 DI=0000DS=0C69 ES=0C69 SS=0C79 CS=0C79 IP=0003 NV UP EI PL NZ NA PO NC0C79:0003 8ED0 MOV SS,AXtAX=2000 BX=0000 CX=0016 DX=0000 SP=0000 BP=0000 SI=0000 DI=0000DS=0C69 ES=0C69 SS=2000 CS=0C79 IP=0008 NV UP EI PL NZ NA PO NC0C79:0008 83C40A ADD SP,+0AtAX=2000 BX=0000 CX=0016 DX=0000 SP=000A BP=0000 SI=0000 DI=0000DS=0C69 ES=0C69 SS=2000 CS=0C79 IP=000B NV UP EI PL NZ NA PE NC0C79:000B 58 POP AXd 2000:0 f2000:0000 00 20 00 00 0B 00 79 0C80 06 79 0C 80 06 00 1F . ....y...y.....tAX=0C79 BX=0000 CX=0016 DX=0000 SP=000C BP=0000 SI=0000 DI=0000DS=0C69 ES=0C69 SS=2000 CS=0C79 IP=000C NV UP EI PL NZ NA PE NC0C79:000C 5B POP BXd 2000:0 f2000:0000 00 20 79 0C 00 00 0C 0079 0C 80 06 80 06 00 1F . y.....y.......tAX=0C79 BX=0680 CX=0016 DX=0000 SP=000E BP=0000 SI=0000 DI=0000DS=0C69 ES=0C69 SS=2000 CS=0C79 IP=000D NV UP EI PL NZ NA PE NC0C79:000D 50 PUSH AXd 2000:0 f2000:0000 00 20 79 0C 79 0C 00 000D 00 79 0C 80 06 00 1F . .....y.....tAX=0C79 BX=0680 CX=0016 DX=0000 SP=000C BP=0000 SI=0000 DI=0000DS=0C69 ES=0C69 SS=2000 CS=0C79 IP=000E NV UP EI PL NZ NA PE NC0C79:000E 53 PUSH BXd 2000:0 f2000:0000 00 20 79 0C 00 00 0E 0079 0C 80 06 79 0C 00 1F . y.....y...y...tAX=0C79 BX=0680 CX=0016 DX=0000 SP=000A BP=0000 SI=0000 DI=0000DS=0C69 ES=0C69 SS=2000 CS=0C79 IP=000F NV UP EI PL NZ NA PE NC0C79:000F 58 POP AXd 2000:0 f2000:0000 79 0C 00 00 0F 00 79 0C80 06 80 06 79 0C 00 1F y.....y.....y...tAX=0680 BX=0680 CX=0016 DX=0000 SP=000C BP=0000 SI=0000 DI=0000DS=0C69 ES=0C69 SS=2000 CS=0C79 IP=0010 NV UP EI PL NZ NA PE NC0C79:0010 5B POP BXd 2000:0 f2000:0000 79 0C 80 06 00 00 10 0079 0C 80 06 79 0C 00 1F y.......y...y...tAX=0680 BX=0C79 CX=0016 DX=0000 SP=000E BP=0000 SI=0000 DI=0000DS=0C69 ES=0C69 SS=2000 CS=0C79 IP=0011 NV UP EI PL NZ NA PE NC0C79:0011 B8004C MOV AX,4C00tAX=4C00 BX=0C79 CX=0016 DX=0000 SP=000E BP=0000 SI=0000 DI=0000DS=0C69 ES=0C69 SS=2000 CS=0C79 IP=0014 NV UP EI PL NZ NA PE NC0C79:0014 CD21 INT 21pProgram terminated normallyq實(shí)驗(yàn)3 編程、編譯、連接、跟蹤 (3)PSP的頭兩個字節(jié)是CD20，查看PSP的內(nèi)容。Microsoft(R) Windows DOS(C)Copyright Microsoft Corp 19902001.C:\DOCUME~1\ADMINI~1debug rAX=0000 BX=0000 CX=0016 DX=0000 SP=0000 BP=0000 SI=0000 DI=0000DS=0C69 ES=0C69 SS=0C79 CS=0C79 IP=0000 NV UP EI PL NZ NA PO NC0C79:0000 B80020 MOV AX,2000d 0c69:00C69:0000 CD 20 FF 9F 00 9A F0 FE1D F0 4F 03 80 06 8A 03 . ........O.....0C69:0010 80 06 17 03 80 06 6F 0601 01 01 00 02 FF FF FF ......o.........0C69:0020 FF FF FF FF FF FF FF FFFF FF FF FF 2D 0C 4C 01 .............0C69:0030 40 0B 14 00 18 00 69 0CFF FF FF FF 00 00 00 00 @.....i.........0C69:0040 05 00 00 00 00 00 00 0000 00 00 00 00 00 00 00 ................0C69:0050 CD 21 CB 00 00 00 00 0000 00 00 00 00 20 20 20 .!...........0C69:0060 20 20 20 20 20 20 20 2000 00 00 00 00 20 20 20 .....0C69:0070 20 20 20 20 20 20 20 2000 00 00 00 00 00 00 00 ........q （1）下面的程序?qū)崿F(xiàn)依次用內(nèi)存0:0~0:15單元中的內(nèi)容改寫程序中的數(shù)據(jù)，完成程序：assume cs:codesg codesg segment dw 0123h,0456h,0789h,0abch,0defh,0fedh,0cbah,0987h start: mov ax,0 mov ds,ax mov bx,0 mov cx,8 s: mov ax,[bx] mov cs:[bx],ax add bx,2 loop s mov ax,4c00h int 21h codesg ends end startC:\DOCUME~1\ADMINI~1debug u0C79:0010 B80000 MOV AX,00000C79:0013 8ED8 MOV DS,AX0C79:0015 BB0000 MOV BX,00000C79:0018 B90800 MOV CX,00080C79:001B 8B07 MOV AX,[BX]0C79:001D 2E CS:0C79:001E 8907 MOV [BX],AX0C79:0020 83C302 ADD BX,+020C79:0023 E2F6 LOOP 001B0C79:0025 B8004C MOV AX,4C000C79:0028 CD21 INT 210C79:002A 7503 JNZ 002F0C79:002C E97BFF JMP FFAA0C79:002F 5E POP SIg 0025AX=0680 BX=0010 CX=0000 DX=0000 SP=0000 BP=0000 SI=0000 DI=0000DS=0000 ES=0C69 SS=0C79 CS=0C79 IP=0025 NV UP EI PL NZ AC PO NC0C79:0025 B8004C MOV AX,4C00d 0:0 f0000:0000 68 10 A7 00 BB 13 80 0616 00 A5 03 B1 13 80 06 h...............d 0c79:0 f0C79:0000 68 10 A7 00 BB 13 80 0616 00 A5 03 B1 13 80 06 h...............tAX=4C00 BX=0010 CX=0000 DX=0000 SP=0000 BP=0000 SI=0000 DI=0000DS=0000 ES=0C69 SS=0C79 CS=0C79 IP=0028 NV UP EI PL NZ AC PO NC0C79:0028 CD21 INT 21pProgram terminated normallyqC:\DOCUME~1\ADMINI~1 （2）下面的程序?qū)崿F(xiàn)依次用內(nèi)存0:0~0:15單元中的內(nèi)容改寫程序中的數(shù)據(jù)，數(shù)據(jù)的傳送用棧來進(jìn)行。?？臻g設(shè)置在程序內(nèi)。完成程序：assume cs:codesg codesg segment dw 0123h,0456h,0789h,0abch,0defh,0fedh,0cbah,0987h dw 0,0,0,0,0,0,0,0,0,0 start: mov ax, codesg 。或mov ax, cs mov ss,ax mov sp, 24h 。或mov sp, 36 。(第一版填1ah或26) mov ax,0 mov ds,ax mov bx,0 mov cx,8 s: push [bx] pop cs:[bx] ?；?pop ss:[bx] add bx,2 loop s mov ax,4c00h int 21h codesg ends end startC:\DOCUME~1\ADMINI~1debug u0C86:0024 B8860C MOV AX,0C860C86:0027 8ED0 MOV SS,AX0C86:0029 BC2400 MOV SP,00240C86:002C B80000 MOV AX,00000C86:002F 8ED8 MOV DS,AX0C86:0031 BB0000 MOV BX,00000C86:0034 B90800 MOV CX,00080C86:0037 FF37 PUSH [BX]0C86:0039 2E CS:0C86:003A 8F07 POP [BX]0C86:003C 83C302 ADD BX,+020C86:003F E2F6 LOOP