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基于psat的電力系統(tǒng)潮流計(jì)算仿真(編輯修改稿)

2024-10-25 16:01 本頁(yè)面
 

【文章內(nèi)容簡(jiǎn)介】 ./(B1(i3)*B1(i5)^2+B1(i4)./2P=real(S)。Q=imag(S)。[C,D,DF]=xxf(G,B,e,f,P,Q,n,B2,ph,V,no)。J=jacci(Y,G,B,P,Q,e,f,V,C,D,B2,n,ph,no)。[De,Di]=hxf(J,D,F,ph,n,no)。t=0。whilemax(abs(De))ipamp。max(abs(Dfi)ipt=t+1。e=e+De;f=f+Df。[C,D,DF]=xxf(G,B,e,f,P,Q,n,B2,ph,V,no);J=jacci(Y,G,B,P,Q,e,f,V,C,D,B2,n,ph,no);[De,Df]=hxf(J,Df,ph,n,no)。end v=e+f*j。for i=1:n hh(i)=conj(Y(ph,i)*v(i))。end S(ph)=sum(hh)*v(ph)。B2(ph,1)=S(ph)。V=abs(v)。jd=angle(v)*180/p。resulte1=[A(:,1),real(v),imag(v),V,jd,real(S’),imag(S’),real(B2(:1)),imag(B2(:1)),real(B2(:2)),imag(B2(:,2))]。for i=1:ma(i)=conj((v(B1(i1))/B1(i5)v(B1(i2))/B1(i3))。b(i)=v(B1(i1))*a(i)j*B1(i4)*v(B1(i))^2/2。c(i)=v(B1(i2))*a(i)j*B1(i4)*v(B1(i2))^2/2。end result2=[B1(:,6),B1(:,1),B1(:,2),real(b’),imag(b’),real(c’),imag(c’), real(b’+c’),imag(b’+c’)]。printcut(result1,S,b,c,result2)。type resultm function [C,D,Df]=xxf(G,B,e,f,P,Q,n,B2,ph,V,no)%該子程序是用來(lái)求取Df for i=1:nIfi=phC(i)=0。D(i)=0。For j=i:nC(i)=C(i)+G(i,j)*e(j)B(i,j)*f(j)。D(i)=D(i)+G(i,j)*f(j)+B(i,j)*e(j)。endP1=C(i)*e(i)+D(i)*f(i)。Q1=C(i)*f(i)D(i)*e(i)。V1=e(i)^2+f(i)^2。IfB2(i4)=2 p=2*i1。Df(p)=P(i)P1。p=p+1。else p=2*i1。Df(p)=P(i)P1。p=p+1。Df(p)=Q(i)Q1。end end end Df=Df’。If ph=n Df(noJ=[]。endfunction [De,Df]=hxf(J,Df,ph,n,no)%該子函數(shù)是為求取De Df DX=JDf。DX1=DX。x1=length(DX1)。if ph=n DX(no)=0。DX(no+1)=0。For i=(no+2):(x1+2)DX(i)=DX1(i2)。End ElseDX=[DX1,0,0]。End k=0。[x,y]=size(DX)。For i=1:2:x K=k+1。Df(k)=DX(i)。De(k)=DX(i+1)。End End case 2 Function for j=1:n J=jacci(Y,G,B,PQ,e,f,V,C,D,B2,n,ph,no)X1=G(i,j)*f(i)B(i,j)*e(i)。X2=G(i,j)*e(i)+B(i,j)*f(i)。%該子程序是用來(lái)求取jacci矩陣for i=1:n X3=0。switch B2(i4)X4=0。case 3 P=2*i1。continue q=2*j1。case 1 J(p,q)=X1。for j=1:n m=p+1。ifJ=amp。J=ph J(m,q)=X3。X1=G(i)*f(i)B(i,j)*e(i)。q=q+1。X2=G(i,j)*e(i)+B(i,j)*f(i)。J(p,q)=X2。X3=X2。J(m,q)=X4。X4=X1。X1=D(i)+G(i,j)*f(i)B(i,j)*e(i)。p=2*i1。X2=C(i)+G(i,j)*e(i)+B(i,j)*f(i)。q=2*j1。X3=0。J(p,q)=X1。X4=0。m=p+1。P=2*i1。J(p,q)=X2。q=2*j1。J(m,q)=X4。J(p,q)=X1。Else if j=amp。j=jph m=p+1。X1=D(i)+G(i,j)*f(i)B(i,j)*e(i)。J(m,q)=X3。X2=C(i)+G(i,j)*e(i)+B(i,j)*f(i)。q=q+1。X3= C(i)+G(i,j)*e(i)B(i,j)*f(i)。J(p,q)=X2。X4= C(i)+G(i,j)*f(i)B(i,j)*e(i)。J(m,q)=X4。P=2*i1。end q=2*j1。end J(p,q)=X1。end m=p+1。end J(m,q)=X3。if ph=n q=q+1。J(no:)=[]。J(p,q)=X2。J(no:)=[]。J(m,q)=X4。J(:,no)=[]。End J(:,no)=[]。End2實(shí)例驗(yàn)證 【例題】設(shè)有一系統(tǒng)網(wǎng)絡(luò)結(jié)線見(jiàn)圖1,各支路阻抗和各節(jié)點(diǎn)功率均已以標(biāo)幺值標(biāo)示于圖1中,其中節(jié)點(diǎn)2連接的是發(fā)電廠,設(shè)節(jié)點(diǎn)1電壓保持U1=,試計(jì)算其中的潮流分布,請(qǐng)輸入節(jié)點(diǎn)數(shù):n=5 請(qǐng)輸入支路數(shù):m=7 請(qǐng)輸入平衡母線的節(jié)點(diǎn)號(hào):ph=l 請(qǐng)輸入支路信息:BI=[ l 2 0.02+0.06i O l 1;1 3 0.08+0.24i 0 1 2;2 3 0.06+0.18i 0 l 3: 2 4 0.06+0.18i O l 4: 2 5 0.04+0.12i 0 l 5: 3 4 0.01+0.03i 0 l 6: 4 5 0.08+0.24i O 1 7] 請(qǐng)輸入節(jié)點(diǎn)信息:B2=[ 0 0 1.06 3;0.2+0.20i 0 1 1;一O.45一O.15i 0 l l;一0.40.05i 0 l 1;一0.6—0.1i 0 1 l] 請(qǐng)輸入節(jié)點(diǎn)號(hào)及對(duì)地阻抗: A=[l 0;2 0;3 0;4 0;5 O ] 請(qǐng)輸入修正值:ip=0.000 0l參考文獻(xiàn)[1]陳珩.電力系統(tǒng)穩(wěn)定分析[M].北京:中國(guó)電力出版社,2002:139—187.[2]鄭阿奇.MATLAB實(shí)用教程[M].北京:電子工業(yè)出版社,2005:1243.[3] 束洪春,孫士云,等.云電送粵交商流混聯(lián)系統(tǒng)全過(guò) 程動(dòng)態(tài)電壓研究[J】.中國(guó)電力,2008,4l(10):l4. 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