生產(chǎn)者理論知識(編輯修改稿)
2025-03-06 18:19 本頁面
【文章內(nèi)容簡介】 G(z?) =`Q G(z) `Q But what if we changed some of the assumptions here? _ Z(Q) Case 1: Z is smooth and strictly convex z 1 z 2 _ Z(Q) ? z ? ? z? Pick any two points in Z Draw the line between them Intermediate points must lie in Z meaning: a bination of feasible techniques is also feasible Case 2: Z convex but not strictly convex z 1 z 2 _ Z(Q) This region causes a problem meaning: in this region there is an indivisibility Case 3: Z is smooth but not convex An Example... London New York 3 1 3 1 z 1 z 2 slope undefined at this point the only efficient point for Q =`Q _ Z(Q) Case 4: Z is convex but not smooth z 1 z 2 z 1 z 2 z 1 z 2 z 1 z 2 Standard case, but strong assumptions about divisibility and smoothness almost conventional case: mixtures may be just as good as single techniques Presents problems: the dent represents an indivisibility unusual case : only one efficient point and not smooth. But not perverse. Summary: 4 possibilities for the input requirement set Z { z : G(z) = Q } This is the isoquant. Let39。s look at its shape... ? Pick an output level Q ? Fin
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