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t a n2070s i n30s i n50s i n10s i n)10的定義域求定義在))21( c o s],41,0[)()51t a n)32c o s (ln4 ) y 32s i n22t a n)3)23( c o sl o gs i n21)2t a n2c o sl o g2122?????????????xfxfxxxxyxxyxxy?二:求定義域 ]2,2[,c o ss i nc o ss i n)5c o sc o ss i n2s i n3)4c o ss i n32c o s21)31s i nc o s3)2]2,2[,2c o ss i n122?????????????????????xxxxxyxxxxyxxxyxxyxxxy)三。求值域、最值 xxxyxxyc oss i n1s i n7) c os2s i n3)6?????的取值范圍。求都有若axfxaxxxf,2|)(|]2,0[,2s i n3c o s2)(.22???????02c oss i n2.32 有解的方程為何值時(shí),關(guān)于實(shí)數(shù)??? mxxxm的最值值,并求此時(shí)的)求使(表達(dá)式)寫出(最小值記為)(21)(2)(1)(s i n