微機(jī)原理習(xí)題參考答案(黃冰版)(編輯修改稿)
2025-07-25 18:19 本頁(yè)面
【文章內(nèi)容簡(jiǎn)介】 START: MOV AX, DATA MOV DS, AX MOV CX, n MOV SI, OFFSET BUF MOV DI, OFFSET BUF1 MOV BX, OFFSET BUF2 LOP1: MOV AX, [SI] INC SI INC SI CMP AX, 0000H JGE NEXT1 MOV [BX], AX ADD BX, 02H JMP LOP2 NEXT1: MOV [DI], AX ADD DI, 2 LOP2: LOOP LOP1 MOV AH, 4CH INT 21H CODE ENDS END STARTSTACK SEGMENT STACK DB 256 DUP（?）STACK ENDS DATA SEGMENT BUF DB ‘This is a string’,’$’DATA ENDSCODE SEGMENT ASSUME CS:CODE. DS:DATA。 SS:STACKSTART: MOV AX, DATA MOV DS, AX MOV SI,OFFSET BUF TACKCHAR: MOV DL,[SI] CMP DL,’$’ JZ DONE CMP DL,’a’ JB NEXT SUB DL,20H NEXT: MOV AH,02H INT 21H INC SI MP TAKECHAR DONE: MOV AH,4CH INT 21H CODE ENDS END START3．20 DATA_SEG SEGMENT DATX DB ? DATY DB ? DATZ DB ?DATA_SEG ENDSCODE SEGMENT ASSUME CS:CODE, DS:DATA_SEGSTART: MOV AX,DATA_SEG MOV DS,AXMOV AL,DATXMOV BL,DATY CMP AL,BL JS NEXT MOV DATZ,AL JMP DONENEXT: MOV DATZ,BLDONE: MOV AH,4CH INT 21HCODE ENDSEND STARTDATA_SEG SEGMENT DATA DB ? DATB DB ? DATC DB ? DATD DB ?DATA_SEG ENDSCODE SEGMENT ASSUME CS:CODE, DS:DATA_SEGSTART: MOV AX,DATA_SEG MOV DS,AX CMP DATA,0 JZ NEXT CMP DATB,0 JZ NEXT CMP DATC,0 JZ NEXT MOV AL,DATA ADD AL,DATB ADC AL,DATC MOV DATD,AL JMP DONENEXT: MOV DATA,0MOV DATB,0 MOV DATC,0DONE: MOV AH,4CHINT 21HCODE ENDSEND START ,將結(jié)果存入字符變量HEXNUM中。HEXNUM變量中原來(lái)的內(nèi)容未知，程序段執(zhí)行后的內(nèi)容是字符A的十六進(jìn)制數(shù)0ADATA_SEG SEGMENT N=10DATA1 DB N DUP(?) DATA2 DB N DUP(?) ADR1 DW ? ADR2 DW ? DATA_SEG ENDSCODE SEGMENT ASSUME CS:CODE, DS:DATA_SEGSTART: MOV AX, DATA_SEGMOV DS, AXLEA SI, DATA1LEA DI,DATA2MOV CX, NLOP1: MOV AH,[SI]CMP AH,[DI] JNZ NOTEQUINC SIINC DILOOP LOP1MOV AH,0FFHSAHFJMP DONENOTEQU: MOV AH,0SAHFMOV ADR1,[SI]MOV ADR2,[DI]DONE:MOV AH,4CHINT 21HCODE ENDSEND STARTDATA_SEG SEGMENTCOUNT=100BUF DB COUNT NUP(?) MAX DB ?DATA_SEG ENDSCODE SEGMENT ASSUME CS:CODE, DS:DATA_SEGSTART: MOV AX, DATA_SEG MOV DS, AXMOV SI, OFFSET BUFMOV CX,COUNTLOP1: MOV AH,1INT 21HMOV [SI], ALINC SILOOP LOP1MOV SI,OFFSET BUFMOV CX,COUNTMOV AL, [SI]LOP2:CMP AL, [SI+1]JA NEXT2XCHG AL,[SI+1]INC SINEXT2:LOOP LOP2MOV MAX,ALMOV AH, 4CHINT 21HCODE ENDSEND STARTDATA_SEG SEGMENT BUF DB 10 DUP(?)STR1 DB ‘Do you want input number(y/n)?’,0DH,0AH,’$’STR2 DB ‘Please input the numbers’ ,0DH,0AH,’$’ MAX DB ? MIN DB ?DATA_SEG ENDSCODE SEGMENT ASSUME CS:CODE, DS:DATA_SEGSTART: MOV AX, DATA_SEGMOV DS, AXMOV DX,OFFSET STR1MOV AH,09HINT 21HMOV DX,OFFSET STR2MOV AH,09HINT 21HMOV SI, OFFSET BUFMOV CX,10LOP1:MOV AH,1INT 21HMOV [SI], ALINC SILOOP LOP1MOV SI,OFFSET BUFMOV CX,9MOV AL, [SI]LOP2:CMP AL, [SI+1]JA NEXT2XCHG AL,[SI+1]INC SINEXT2:LOOP LOP2MOV MAX,ALMOV SI,OFFSET BUFMOV CX,9MOV AL, [SI]LOP3: CMP AL, [SI+1]JB NEXT3XCHG AL,[SI+1]INC SINEXT3:LOOP LOP3MOV MIN,ALMOV AH,4CHINT 21HCODE ENDSEND STARTDATA SEGMENTBUFF DB 10 DUP(?)DATA ENDSCODE SEGMENT ASSUME CS:CODE, DS:DATASTART: MOV AX,DATAMOV DS,AXMOV
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