【文章內(nèi)容簡(jiǎn)介】 設(shè)備窗口、串口通訊父設(shè)備基本屬性設(shè)置：串口端口號(hào)，選擇“0COM1”，數(shù)據(jù)位位數(shù)38位，停止位為1位，數(shù)據(jù)校驗(yàn)方式為偶校驗(yàn)，數(shù)據(jù)采集方式為同步采集，通信波特率為9600,通訊方式選擇本地串口通訊[20]?！盎緦傩浴睒?biāo)簽中的“內(nèi)部屬性”選項(xiàng)，進(jìn)入“內(nèi)部屬性”設(shè)置,在該窗口下可進(jìn)行增加或刪除通道等操作。 串口通訊父設(shè)備屬性設(shè)置窗口 松下FP系列PLC基本屬性 松下FP系列PLC通道屬性和通道連接設(shè)置 通道連接的參數(shù)列表設(shè)備1通道對(duì)應(yīng)數(shù)據(jù)對(duì)象通道類(lèi)型周期設(shè)備2通道對(duì)應(yīng)數(shù)據(jù)對(duì)象通道類(lèi)型周期1T1C1XW讀X000011T2C1XW讀X000012T1C2XW讀X000112T2C2XW讀X000113T1C3XW讀X000213T2C3XW讀X000214T1C4XW讀X000314T2C4XW讀X000315T1C5XW讀X000415T2C5XW讀X000416T1KMXW讀X000516T2KMXW讀X000517T1GMXW讀X000617T2GMXW讀X000618T1SXXW讀X000718T2SXXW讀X000719T1XXXW讀X000819T2XXXW讀X0008110T1C1讀寫(xiě)Y0000110T2C1讀寫(xiě)Y0000111T1C2讀寫(xiě)Y0001111T2C2讀寫(xiě)Y0001112T1C3讀寫(xiě)Y0002112T2C3讀寫(xiě)Y0002113T1C4讀寫(xiě)Y0003113T2C4讀寫(xiě)Y0003114T1C5讀寫(xiě)Y0004114T2C5讀寫(xiě)Y0004115T1S1讀寫(xiě)Y0005115T2S1讀寫(xiě)Y0005116T1S2讀寫(xiě)Y0006116T2S2讀寫(xiě)Y0006117T1X2讀寫(xiě)Y0007117T2X2讀寫(xiě)Y0007118T1S3讀寫(xiě)Y0008118T2S3讀寫(xiě)Y0008119T1X3讀寫(xiě)Y0009119T2X3讀寫(xiě)Y0009120T1S4讀寫(xiě)Y000A120T2S4讀寫(xiě)Y000A121T1X4讀寫(xiě)Y000B121T2X4讀寫(xiě)Y000B122T1X5讀寫(xiě)Y000C122T2X5讀寫(xiě)Y000C1 電梯監(jiān)控系統(tǒng)調(diào)試 電梯監(jiān)控系統(tǒng)的模擬調(diào)試電梯監(jiān)控系統(tǒng)的監(jiān)控畫(huà)面編輯好，并進(jìn)行動(dòng)畫(huà)連接后，在運(yùn)行策略中完成了相關(guān)的策略和腳本程序編輯。工程中的用戶程序編寫(xiě)好后，要進(jìn)行在線調(diào)試，在進(jìn)行現(xiàn)場(chǎng)的調(diào)試過(guò)程中，可以借助一些模擬手段來(lái)進(jìn)行初調(diào)。模擬調(diào)試的目的是對(duì)現(xiàn)場(chǎng)的數(shù)據(jù)進(jìn)行模擬，檢查動(dòng)畫(huà)效果和控制流程是否正確，從而達(dá)到與外部設(shè)備進(jìn)行可靠的連接?；诒敬慰刂屏鞒淘O(shè)計(jì)，在電梯模擬調(diào)試的過(guò)程中仍然存在許多的問(wèn)題，模擬控制不能很好地按實(shí)際的控制要求運(yùn)行，這樣將給電梯的現(xiàn)場(chǎng)調(diào)試帶來(lái)許多的不便。目前，仍然存在的問(wèn)題可歸結(jié)如下：一是，電梯門(mén)在半開(kāi)的時(shí)候，按下手動(dòng)關(guān)門(mén)按鈕，電梯門(mén)不能完全關(guān)閉。二是，電梯門(mén)的移動(dòng)和轎廂的移動(dòng)有時(shí)能準(zhǔn)確地移動(dòng)到位，有時(shí)卻不能準(zhǔn)確地到位。三是，電梯在下行運(yùn)行的過(guò)程中，從五層、四層、三層前往二層時(shí)出現(xiàn)錯(cuò)誤，電梯總是停在三層，但二層電梯的門(mén)卻打開(kāi)了，呼叫結(jié)束后五層、四層、三層的指示仍然是亮的。四是，一層的開(kāi)門(mén)手動(dòng)按鈕不能達(dá)到手動(dòng)控制的目的。五是，在電梯上行或下行的過(guò)程中，不能同時(shí)響應(yīng)多個(gè)呼叫按鈕，這是與實(shí)際不相符的。 電梯監(jiān)控系統(tǒng)的現(xiàn)場(chǎng)調(diào)試一項(xiàng)工程完成最終是要與實(shí)際的設(shè)備進(jìn)行連接，并能可靠連接和正常通信的。設(shè)計(jì)的監(jiān)控系統(tǒng)是否可行，這就要求監(jiān)控系統(tǒng)能與實(shí)際設(shè)備連接，進(jìn)行現(xiàn)場(chǎng)的調(diào)試?，F(xiàn)場(chǎng)調(diào)試后能與設(shè)備正常通信，滿足系統(tǒng)的控制要求，這樣的一個(gè)監(jiān)控系統(tǒng)才算是真正的完成了，這樣的監(jiān)控系統(tǒng)才是有實(shí)用價(jià)值的，才能投入現(xiàn)場(chǎng)運(yùn)行。在現(xiàn)場(chǎng)的調(diào)試的過(guò)程中，可在“設(shè)備窗口”中的“設(shè)備調(diào)試”窗口觀察到，當(dāng)系統(tǒng)連接成功后，其最上面的通信狀態(tài)標(biāo)志應(yīng)為“0”，任何非“0”的標(biāo)志都表示系統(tǒng)連接失敗。5 總結(jié)為期一個(gè)學(xué)期的畢業(yè)設(shè)計(jì)已臨近尾聲，各項(xiàng)的設(shè)計(jì)任務(wù)已經(jīng)基本完成。在這畢業(yè)設(shè)計(jì)的過(guò)程中，有過(guò)許多的茫然和艱辛，也有許多的驚喜和期待。在整個(gè)電梯監(jiān)控系統(tǒng)設(shè)計(jì)的過(guò)程中，當(dāng)自己能用MCGS組態(tài)軟件模擬控制電梯，并讓其動(dòng)起來(lái)，這時(shí)我覺(jué)得這是一個(gè)小小的驚喜，是對(duì)自己這一段工作的肯定。但是也遇到許多的困難，如電梯控制程序調(diào)試時(shí)，常常有許多不理想的動(dòng)作，使調(diào)試不能完成。電梯監(jiān)控系統(tǒng)畫(huà)面的編輯是一個(gè)很重要的過(guò)程，編輯的圖形對(duì)象不僅僅是對(duì)畫(huà)面美觀上的影響，還與其動(dòng)畫(huà)連接的有很大的關(guān)系，這是在動(dòng)畫(huà)連接的過(guò)程中感覺(jué)到的。在整個(gè)設(shè)計(jì)的工作中，最困難的在于電梯控制流程的設(shè)計(jì)，這也是本次設(shè)計(jì)的主要任務(wù)要求。在設(shè)計(jì)的過(guò)程中通過(guò)自己不斷的學(xué)習(xí)和老師的細(xì)心指導(dǎo)，許多問(wèn)題得到了有效的解決，但仍然有存在一些問(wèn)題和設(shè)計(jì)方面的不合理之處。在完成畢業(yè)設(shè)計(jì)的過(guò)程中，有收獲，也有遺憾。說(shuō)收獲，我覺(jué)得自己溫習(xí)了許多的知識(shí)，將以前學(xué)過(guò)的知識(shí)串了一遍，并學(xué)會(huì)了一些思考問(wèn)題和解決問(wèn)題的方法。說(shuō)遺憾，我的畢業(yè)設(shè)計(jì)目前仍然存在許多的問(wèn)題和不合理之處，由于時(shí)間和能力的有限，我不能把它們完成。收獲和遺憾或者說(shuō)失敗，我覺(jué)得它們同樣是重要的。附錄 程序清單第 46 頁(yè) 共 45頁(yè)T1轎廂的垂直控制（上行）：IF T1GMXW = 1 THEN IF T1C2 = 1 THEN 39。由T1C1前往 T1C2T1C1XW = 0 IF T1C1 = 0 AND ( T1C2 = 1 OR T1S2 = 1 ) AND T1C3 = 0 AND T1C4 = 0 AND T1C5 = 0 AND T1C1XW = 0 THEN 定時(shí)器啟動(dòng)16 = 1定時(shí)器復(fù)位16 = 0IF 計(jì)時(shí)時(shí)間16 0 AND 計(jì)時(shí)時(shí)間16 5 THENCZYDL1 = CZYDL1 1ENDIFIF 時(shí)間到16 = 1 THEN 定時(shí)器復(fù)位16 = 1定時(shí)器啟動(dòng)16 = 0T1C2 = 0T1C2XW = 1T1C1ZS = 0T1C2ZS = 1ENDIFENDIFENDIFIF T1C3 = 1 THEN 39。由T1C2前往T1C3T1C2XW = 0IF T1C1 = 0 AND T1C2 = 0 AND （T1C3 = 1 OR T1S3） AND T1C4 = 0 AND T1C5 = 0 AND T1C2XW = 0 AND T1C2ZS = 1 THEN 定時(shí)器啟動(dòng)16 = 1定時(shí)器復(fù)位16 = 0IF 計(jì)時(shí)時(shí)間16 0 AND 計(jì)時(shí)時(shí)間16 5 THENCZYDL1 = CZYDL1 1ENDIFIF 時(shí)間到16 = 1 THEN 定時(shí)器復(fù)位16 = 1定時(shí)器啟動(dòng)16 = 0T1C3 = 0T1C3XW = 1T1C1ZS = 0T1C2ZS = 0T1C3ZS = 1ENDIFENDIFENDIFIF T1C4 = 1 THEN 39。由T1C2前往T1C4T1C2XW = 0IF T1C1 = 0 AND T1C2 = 0 AND T1C3 = 0 AND（ T1C4 = 1 OR T1S4） AND T1C5 = 0 AND T1C2XW = 0 AND T1C2ZS = 1 THEN 定時(shí)器啟動(dòng)16 = 1定時(shí)器復(fù)位16 = 0IF 計(jì)時(shí)時(shí)間16 0 AND 計(jì)時(shí)時(shí)間16 5 THENCZYDL1 = CZYDL1 1ENDIFIF 時(shí)間到16 = 1 THEN 定時(shí)器復(fù)位16 = 1定時(shí)器啟動(dòng)16 = 0ENDIFIF 計(jì)時(shí)時(shí)間16 0 AND 計(jì)時(shí)時(shí)間16 5 THENCZYDL1 = CZYDL1 1ENDIFIF 時(shí)間到16 = 1 THEN 定時(shí)器復(fù)位16 = 1定時(shí)器啟動(dòng)16 = 0T1C4 = 0T1C4XW = 1T1C1ZS = 0T1C2ZS = 0T1C3ZS = 0T1C4ZS = 1ENDIFENDIFENDIFIF T1C5 = 1 THEN 39。由T1C2前往T1C5T1C2XW = 0IF T1C1 = 0 AND T1C2 = 0 AND T1C3 = 0 AND T1C4 = 0 AND （T1C5 = 1 OR T1X5） AND T1C2XW = 0 AND T1C2ZS = 1 THEN 定時(shí)器啟動(dòng)16 = 1定時(shí)器復(fù)位16 = 0IF 計(jì)時(shí)時(shí)間16 0 AND 計(jì)時(shí)時(shí)間16 5 THENCZYDL1 = CZYDL1 1ENDIFIF 時(shí)間到16 = 1 THEN 定時(shí)器復(fù)位16 = 1定時(shí)器啟動(dòng)16 = 0ENDIFIF 計(jì)時(shí)時(shí)間16 0 AND 計(jì)時(shí)時(shí)間16 5 THENCZYDL1 = CZYDL1 1ENDIFIF 時(shí)間到16 = 1 THEN 定時(shí)器復(fù)位16 = 1定時(shí)器啟動(dòng)16 = 0ENDIFIF 計(jì)時(shí)時(shí)間16 0 AND 計(jì)時(shí)時(shí)間16 5 THENCZYDL1 = CZYDL1 1ENDIFIF 時(shí)間到16 = 1 THEN 定時(shí)器復(fù)位16 = 1定時(shí)器啟動(dòng)16 = 0T1C5 = 0T1C5XW = 1T1C1ZS = 0T1C2ZS = 0T1C3ZS = 0T1C4ZS = 0T1C5ZS = 1ENDIFENDIFENDIFIF T1C3 = 1 THEN 39。由T1C1前往T1C3T1C1XW = 0 IF T1C1 = 0 AND T1C2 = 0 AND （T1C3 = 1 OR T1S3） AND T1C4 = 0 AND T1C5 = 0 AND T1C1XW = 0 AND T1C1ZS = 1 THEN 定時(shí)器啟動(dòng)16 = 1定時(shí)器復(fù)位16 = 0IF 計(jì)時(shí)時(shí)間16 0 AND 計(jì)時(shí)時(shí)間16 5 THENCZYDL1 = CZYDL1 1ENDIFIF 時(shí)間到16 = 1 THEN 定時(shí)器復(fù)位16 = 1定時(shí)器啟動(dòng)16 = 0ENDIFIF 計(jì)時(shí)時(shí)間16 0 AND 計(jì)時(shí)時(shí)間16 5 THENCZYDL1 = CZYDL1 1ENDIFIF 時(shí)間到16 = 1 THEN 定時(shí)器復(fù)位16 = 1定時(shí)器啟動(dòng)16 = 0T1C3 = 0T1C3XW = 1T1C1ZS = 0T1C2ZS = 0T1C3ZS = 1ENDIFENDIFENDIFIF T1C4 = 1 THEN 39。由T1C3前往T1C4T1C3XW = 0IF T1C1 = 0 AND T1C2 = 0 AND T1C3 = 0 AND （T1C4 = 1 OR T1S4） AND T1C5 = 0 AND T1C3XW = 0 AND T1C3ZS = 1 THEN 定時(shí)器啟動(dòng)16 = 1定時(shí)器復(fù)位16 = 0IF 計(jì)時(shí)時(shí)間16 0 AND 計(jì)時(shí)時(shí)間16 5 THENCZYDL1 = CZYDL1 1ENDIFIF 時(shí)間到16 = 1 THEN 定時(shí)器復(fù)位16 = 1定時(shí)器啟動(dòng)16 = 0T1C4 = 0T1C4XW = 1T1C1ZS = 0T1C2ZS = 0T1C3ZS = 0T1C4ZS = 1ENDIFENDIFENDIFIF T1C5 = 1 THEN 39。由T1C3前往T1C5T1C3XW = 0IF T1C1 = 0 AND T1C2 = 0 AND T1C3 = 0 AND T1C4 = 0 AND （T1C5 = 1 OR T1X5） AND T1C3XW = 0 AND T1C3ZS = 1 THEN 定時(shí)器啟動(dòng)16 = 1定時(shí)器復(fù)位16 = 0IF 計(jì)時(shí)時(shí)間16 0 AND 計(jì)時(shí)時(shí)間16 5 THENCZYDL1 = CZYDL1 1ENDIFIF 時(shí)間到16 = 1 THEN 定時(shí)器復(fù)位16 = 1定時(shí)器啟動(dòng)16 = 0ENDIFIF 計(jì)時(shí)時(shí)間16 0 AND 計(jì)時(shí)時(shí)間16 5 THENCZYDL1 = CZYDL1 1ENDIFIF 時(shí)間到16 = 1 THEN 定時(shí)器復(fù)位16 = 1定時(shí)器啟動(dòng)16 = 0T1C5 = 0T1C5XW = 1T1C1ZS = 0T1C2ZS = 0T1C3ZS = 0T1C4ZS = 0T1C5ZS = 1ENDIFENDIFENDIFIF T1C4 = 1 THEN 39。由T1C1前往T1C4 T1C1XW = 0IF T1C1 = 0 AND T1C2 = 0 AND T1C3 = 0 AND（ T1C4 = 1 OR T1S4） AND T1C5 = 0 AND T1C1XW = 0