運籌學基礎圖論方法(編輯修改稿)
2025-05-27 12:05 本頁面
【文章內(nèi)容簡介】 幾座橋，才能完全切斷兩岸的交通聯(lián)系？ A D B C D EF A F D E C B 2(0) 1(0) 3(0) 1(0) 2(0) 1(0) 2(0) 1(0) 1(0) A F D E C B 2(0) 1(0) 3(0) 1(0) 2(0) 1(0) 2(0) 1(0) 1(0) (A+,?) (A+,2) (B+,2) (D+,1) A F D E C B 2(1) 1(1) 3(0) 1(0) 2(0) 1(0) 2(1) 1(0) 1(0) (A+,?) (A+,2) (C+,1) (D+,1) (E+,1) A F D E C B 2(1) 1(1) 3(1) 1(0) 2(1) 1(0) 2(1) 1(1) 1(1) (A+,?) (A+,1) (E+,1) A F D E C B 2(1) 1(1) 3(2) 1(0) 2(1) 1(1) 2(1) 1(1) 1(1) (A+,?) (A+,1) (B+,1) (D,1) 至少炸斷橋 A－ E， D－ E， D－ F，才能完全切斷兩岸的交通聯(lián)系 q = 1 q = 1 q = 1 ［例］匹配問題 有三根相同的軸（編號為 1,2,3），又有三個的齒輪（編號為4,5,6），由于精度不高，不能任意匹配，配合情況如圖所示，部如何選擇裝配方案，以得到軸和齒輪的最大數(shù)。 1 2 3 4 5 6 1(0) S t 1(0) 1(0) 1(0) 1(0) 1(0) 1(0) 1(0) 1(0) 1(0) 1(0) 1(0) (s+,?) (s+,1) (1+,1) (4+,1) 1(1) 1 2 3 4 5 6 S t 1(0) 1(0) 1(1) 1(0) 1(0) 1(0) 1(0) 1(0) 1(1) 1(0) 1(0) (s+,?) (s+,1) (2+,1) (5+,1) (s+,?) (s+,1) (3+,1) 1(1) 1 2 3 4 5 6 S t 1(1) 1(0) 1(1) 1(0) 1(1) 1(0) 1(0) 1(0) 1(1) 1(1) 1(0) (5+,1) (2+,1) (6+,1) 1(1) 1 2 3 4 5 6 S t 1(1) 1(1) 1(1) 1(0) 1(0) 1(1) 1(1) 1(0) 1(1) 1(1) 1(1) 1－ 4， 2－ 6， 3－ 5 q = 1 q = 1 q = 1 （五）多端網(wǎng)路問題 1 8 7 6 4 3 5 2 (15, 0) (10, 0) (20,0) (5,0) (5,0) (5,0) (5,0) (5,0) (10,0) (10, 0) (10,0) (10,0) 發(fā)點 1 20 發(fā)點 2 20 收點 1 15 收點 2 20 (5,0) 1 8764352(1 5 , 1 0 )(1 0 , 1 0 )(2 0 , 5 )(5 , 5 )(5 , 5 )(5 , 5 )(5 , 5 )(5 , 0 )(1 0 , 5 )(1 0 , 1 0 )(1 0 , 5 )(1 0 , 0 )虛發(fā)點虛收點st(2 0 , 1 5 )(2 0 , 1 5 )(2 0 , 1 5 )(1 5 , 1 5 )(5 , 0 )事實上 1 8 7 6 4 3 5 2 (15,10) (10,10) (20,5) (5,5) (5,5) (5,5) (5,5) (5,0) (10,5)
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