電力拖動(dòng)自動(dòng)控制系統(tǒng)-運(yùn)動(dòng)控制系統(tǒng)(_阮毅_陳伯時(shí))課后參考答案第三四章(僅供參考)(編輯修改稿)
2025-02-03 22:08 本頁面
【文章內(nèi)容簡介】 ∑??= 校驗(yàn)： 轉(zhuǎn)速環(huán)截止頻率： ?????? = ??????1= ???? ???? = 1）電流環(huán)傳遞函數(shù)簡化條件： 13√??????∑?? = ?????? 滿足簡化條件 2）轉(zhuǎn)速環(huán)小時(shí)間常數(shù)近似處理?xiàng)l件： 13√?????????? = ?????? 滿足近似條件 ???? = ???? ??0 = ???? ???? = ????????= ???? ?????? = 4????????0= ???? (4) 設(shè)理想空載起動(dòng)時(shí) z=0 ????? = ??dN ??????= r/min ???? = 2?????????????(λ?z)???????? ??∑??????= 4% 10% 39 ???????? = ???? = ???? = ???? = 1????= 位置式 PI 調(diào)節(jié)器的表達(dá)式： u(k) = ???? ??(??)+???? ???????? ∑??(??)????=0= ???? ??(??)+ 1???????????? ∑??(??)????=0= ??(??)+∑??(??)????=0 增量式 PI 調(diào)節(jié)器的表達(dá)式： u(k) = u(k?1)+?u(k)= u(k?1)+???? [??(??)???(?? ?1)]+???? ???????? ??(??) == u(k?1)+???? [??(??)???(?? ?1)]+ 1???????????? ??(??)= u(k?1)+[??(??)???(?? ?1)]+??(??) 310 (1) β = ?????????dm =?????????N = ?? = ??????????????? =??????????? = ?????? = ?? ,???? = ?? ?????? = ?? ,???? = ???? = ?? ,???? = ?? ??∑?? = ?????? +???? = ?? 取 ???? ??∑?? = , ???? = 1???? = ??∑?? = 1????+?????? = ?? 取 h=5 ???? = ? ??∑?? = ?? ???? = ? +12?2??∑??2= ???? = (?+1)β???? ????2? ?? ?? ??∑??= ???? = ???? ??0 = ???? ???? = ????????= ???? ?????? = 4????????0= ???? (2) 電流環(huán)截止頻率： ?????? = ???? = 1）校驗(yàn)晶閘管整流裝置傳遞函數(shù)的近似條件： 13???? = ?????? 滿足近似條件 2）校驗(yàn)忽略反電動(dòng)勢變化對(duì)電流環(huán)動(dòng)態(tài)影響的條件： 3√ 1???? ????= ?????? 滿足近似條件 3）校驗(yàn)電流環(huán)小時(shí)間常數(shù)近似處理?xiàng)l件： 13√1???? ?????? = ?????? 滿足近似條件 ?????? 合理 轉(zhuǎn)速環(huán)截止頻率： ?????? = ??????1= ???? ???? = 1）電流環(huán)傳遞函數(shù)簡化條件： 13√??????∑?? = ?????? 滿足簡化條件 2）轉(zhuǎn)速環(huán)小時(shí)間常數(shù)近似處理?xiàng)l件： 13√?????????? = ?????? 滿足近似條件 ??????合理 311 (1) β = ?????????dm = ?? = ??????????????? =??????????? = n = ??????? = 500 ??/?????? ???? = ????0????= ???? ??+??dL ??????= (2) 電動(dòng)機(jī)突然失磁， 轉(zhuǎn)子在原有轉(zhuǎn)速下只能產(chǎn)生較小的感應(yīng)電動(dòng)勢，直流電機(jī)轉(zhuǎn)子電流急劇增加，可能飛車。 若系統(tǒng)能夠穩(wěn)定下來，則穩(wěn)定后 n = 0,???? = 0,????? = ??????? = 10??,???? = ??????? = 10?? , ???? = ??dm = 30A, ???? = ????0????= ???? ?? +??dL ??????= ??dm ??????= 2?? (3) h=5,??rmin = , ??∑?? = ?? ???? = ? +12?2??∑??2= 48 ??ASR(s) = ???
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