matlab優(yōu)化工具箱函數(shù)簡(jiǎn)介-全文預(yù)覽
【正文】 x(1)^2+3*x(2)^2+2*x(1)*x(2)+3*x(2)+1)39。,X0)[x,fval]=fminsearch(39。調(diào)用格式：x=fminunc(fun,X0)x=fminsearch(fun,X0) 以X0為初始迭代點(diǎn)，求使函數(shù)fun取得最小值的x[x,fval]= fminunc(fun,X0)[x,fval]= fminsearch(fun,X0)以X0為初始迭代點(diǎn)，求得最優(yōu)點(diǎn)x和最優(yōu)值fval。(x^5+x^3+x^21)/(exp(x^2)+sin(x))39。 (32*x)^2*x39。x=fminbnd(f,0,)方法3: x = fminbnd((x) (32*x)^2*x,0,)方法4：先形成一個(gè)函數(shù)文件function f=fun(x)f=(32*x)^2*x。(32*x)^2*x39。例：求minf(x)= (32*x)^2*x方法1：x=fminbnd(39。)。,0,)x=fminbnd(fun,0,)若需輸出最優(yōu)點(diǎn)處的目標(biāo)函數(shù)值f，則將上述語句的左邊改為[x,f]，如：[x,f]=fminbnd(39。例：clearfun=39。2． 無約束極小值優(yōu)化工具箱函數(shù) fminunc, fminsearch以上兩個(gè)函數(shù)均可求解無約束多元函數(shù)的最小值。3*x(1)^2+2*x(1)*x(2)+x(2)^239。)例2：clearfun=39。largescale39。display39。tolx39。[x,fval,exitflag,output,grad,hessian]=fminunc(fun,x0,options)3． 約束極小值優(yōu)化工具箱函數(shù) fmincon對(duì)應(yīng)數(shù)學(xué)模型：min F(X) subject to: A*X = B, Aeq*X = Beq (linear constraints)
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