微積分高階導數(shù)ppt課件-wenkub
2023-05-14 02:10:38 本頁面
【正文】 (2lim 2 ??)]()()(2[lim xaxxax ?? ???? ?)(2 a??解 )1l n ()1( 22 xyxey x ???練習：求二階導數(shù)：2223)1(22)2(442)1(:222xxyexxexeyk e y xxx???????????例 . .)( )( nk ynkxy 階導數(shù)的為正整數(shù)求 ?解 )( ??? kxy)()( )( nkn xy ?因此,1?? kkx)( 1 ???? ?kkxy,23)1()1( xkky k ?????? ?????,)1( 2??? kxkk,!)( ky k ? .0)1( ??ky????????? ?knknxnkkk nk,0,)1()1( ?階導數(shù)求任意 ? ? )5(5x例： !5? ? ? )13(11x 0?例 . .c o ss i n 階導數(shù)的和求 nxyxy ??解 xx c o s)( s i n ??)2c o s ()( s i n ????? xx類似地可得 ?,2,1,2πcos)(cos )( ??????? ??? nnxx n)2s in ( ??? x)22s i n ( ???? x)22c o s ()( s i n ??????? xx )23s i n ( ???? x ??? ? ?3,2,1)2s i n(s i n )( ???? nnxx n ?? ?? ?? ? ,2s i ns i n ?????? ???? ?nbaxabax nn? ?? ?? ? .2c o sc o s ?????? ???? ?nbaxabax nn推廣）.n,431,n
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