酶促反應(yīng)動力學(xué)多底物動力學(xué)-在線瀏覽
2025-07-13 22:00本頁面
【正文】 2[A] + k2k3[P] КEP = k1k3[P] + k1k2[A] + k2k3[P] E k1[A] EA k3[P] k3 k1 k2 k2 EP V = k3 [EP]﹣ k3 [E] [P] = (k1k2k3 [A] ﹣ k1k2 k3 [P] ) [E0] (k1k3+k1k2+k2k3)+k1(k2+k2+ k3)[A]+k3 (k1+ k2+k2)[P] = num1[A] ﹣ num2[P] const + coefA [A] + coefP [P] 三 雙底物反應(yīng)動力學(xué) (一 ) 有序雙雙機(jī)制： 1 方程的推導(dǎo)： E + A k1 EA + B k2 (EAB≒ EPQ) k3 EQ + P k1 k2 k3 k4 k4 E + Q E k1[A] EA k1 k4 k4[Q] k2 k2[B] k3[P] EQ (EAB≒ EPQ) k3 ? n=4, m=4, 則 n1線 (3線 )矢量圖數(shù)目為 4 E : EA: EAB: EQ: k4 k1[A] k3[P] k1 k1[A] k4[Q] k4[Q] k3[P] k3[P] k2[B] k2[B] k2[B] k3[P] k1 k1 k1 k4 k4 k4 k3 k3 k2[B] k2 k2 k1 k1 k1[A] k4[Q] k4[Q] k4[Q] k3 k3 k3 k2[B] k2[B] k2 k1[A] k1[A] k1[A] k4 k4 k4[Q] k3[P] k3[P] k3 k2 k2 k2 V=k4[EQ] – k4[E][Q] =(k4?К EQ – k4[Q]?К E) [E0]／ ∑К = num1[A][B] num2[P][Q] const + coefA [A] + coefB[B] + coefP[P] + coefQ[Q] + coefAB[A][B]+coefAP[A][P]+coefBQ[B][Q] +coefPQ[P][Q] + coefABP[A][B][P] +coefBPQ[B][P][Q] ? 若不考慮產(chǎn)物的影響，即 [P]=0, [Q]=0 初速度 V= num1[A][B] const + coefA[A] + coefB[B ]+ coefAB[A][B] 2 動力學(xué)常數(shù)的定義： ? 最大反應(yīng)速度： 正向： Vmf= num1 逆向： Vmr= num2 coefAB coefAB ? 米氏常數(shù)： KmA= coefB KmB= coefA coefAB coefAB KmP= coefQ KmQ= coefP coefPQ coefPQ ? 解離常數(shù)： KiA = const KiB = const coefA coefB KiP = const KiQ = const coefP coefQ V = num1[A][B]
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