【正文】
sKMMsKtgydxydss?????????????????????????的圓:半徑為直線:點(diǎn)的曲率:弧長。反三角函數(shù)性質(zhì): a r c c tg xa r c tg xxx ???? 2a r c c o s2a r c s i n ?? ??????????23333133c o s3c o s43c o ss in4s in33s intgtgtgtg?????????????????????222222122212s i nc o ss i n211c o s22c o sc o ss i n22s i ntgtgtgct gct gct g??????????? 3 導(dǎo)數(shù)公式: 基本積分表: 三角函數(shù)的有理式積分: 2222 1 2211co s1 2s i n ududxxtguuuxuux ???????? , , , axxaaact gxxxtgxxxxct gxxtgxaxxln1)( lo gln)(c s c)( c s cs ec)( s ecc s c)(s ec)(22????????????????222211)(11)(11)( ar c c o s11)( ar c s inxarcct gxxarct gxxxxx????????????????????? ?? ??????????????????????????CaxxaxdxCsh xc h x d xCc h xsh x d xCaadxaCxc tg x d xxCxdxtg xxCc tg xx d xxdxCtg xx d xxdxxx)ln (lnc s cc s cs ecs ecc s cs ins ecc o s22222222CaxxadxCxaxaaxadxCaxaxaaxdxCaxa rc tgaxadxCc tg xxx d xCtg xxx d xCxc tg xd xCxtg x d x???????????????????????????????????a r c s inln21ln211c s clnc s cs eclns ecs inlnc o sln22222222???????????????????????????? ?CaxaxaxdxxaCaxxaaxxdxaxCaxxaaxxdxaxInnx d xx d xI nnnna r c s i n22ln22)l n (221c o ss i n222222222222222222222020?? 4 高階導(dǎo)數(shù)公式 —— 萊布尼茲( Leibniz)公式: )()()()2()1()(0)()()(!)1()1(!2)1()(nkknnnnnkkknknnuvvuk knnnvunnvnuvuvuCuv???????????????????????? 中值定理與導(dǎo)數(shù)應(yīng)用: 拉格朗日中值定理。正弦定理: RCcBbAa 2s ins ins in ??? 倍角公式: 和差角公式: α sinα cosα tgα ctgα 360176。α cosα sinα ctgα tgα 270176。α sinα cosα tgα ctgα 180176。α cosα sinα ctgα tgα 90176。 1 高等數(shù)學(xué)公式 手冊 一些初等函數(shù): 兩個重要極限: 三角函數(shù)公式: 誘導(dǎo)公式: 函數(shù) 角 A sin cos tg ctg α sinα cosα tgα ctgα 90176。+α cosα sinα ctgα tgα 180176。+α sinα cosα tgα ctgα 270176。+α cosα sinα ctgα tgα 360176。+α sinα cosα tgα ctgα 和差化積公式: 2s in2s in2c o sc o s2c o s2c o s2c o sc o s2s in2c o s2s ins in2c o s2s in2s ins in????????????????????????????????????????????????????????????????c tgc tgc tgc tgc tgtgtgtgtgtg?????????????1)(1)(s ins inc o sc o s)c o s (s inc o sc o ss in)s in (???xxa rth xxxa rch xxxa rsh xeeeech xsh xth xeech xeesh xxxxxxxxx??????????????????????11ln21)1ln (1ln (:2:2:22)雙曲正切雙曲余弦雙曲正弦...59 04 571 82 81 8 28 )11(li