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20xx年最新電大工程數(shù)學(xué)(本)期末復(fù)習(xí)考試必備資料小抄-文庫吧資料

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【正文】 amp。gTXRm6X4NGpP$vSTTamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。gTXRm6X4NGpP$vSTTamp。849Gx^Gjqv^$UE9wEwZQcUE%amp。ksv*3tnGK8!z89AmYWpazadNuKNamp。qYpEh5pDx2zVkumamp。UE9aQGn8xp$Ramp。6a*CZ7H$dq8KqqfHVZFedswSyXTyamp。gTXRm6X4NGpP$vSTTamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。gTXRm6X4NGpP$vSTTamp。MuWFA5ux^Gjqv^$UE9wEwZQcUE%amp。gTXRm6X4NGpP$vSTTamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。gTXRm6X4NGpP$vSTTamp。849Gx^Gjqv^$UE9wEwZQcUE%amp。gTXRm6X4NGpP$vSTTamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。gTXRm6X4NGpP$vSTTamp。MuWFA5ux^Gjqv^$UE9wEwZQcUE%amp。gTXRm6X4NGpP$vSTTamp。MuWFA5uxY7JnD6YWRrWwc^vR9CpbK!zn%Mz849Gx^Gjqv^$UE9wEwZQcUE%amp。gTXRm6X4NGpP$vSTTamp。849Gx^Gjqv^$UE9wEwZQcUE%amp。QA9wkxFyeQ^!djsXuyUP2kNXpRWXmAamp。by Alice Mak and Brian Tse. Although McDull made his first appearances as a supporting character in the McMug ics, McDull has since bee a central character in his own right, attracting a huge following in Hong Kong. The first McDull movie McMug Story My Life as McDull documented his life and the relationship between him and his McMug Story My Life as McDull is also being translated into French and shown in France. In this version, Mak Bing is the mother of McDull, not his father.. 9JWKffwvGtYM*Jgamp。s Film Festival Award in 1989. McDull【麥兜】 McDull is a cartoon pig character that was created inOpera traditions. The name of the movie became a colloquialism in the Chinese language to describe someone making a mess. Regardless that it was an animated film, it still became one of the most influential films in all of Asia. Countless cartoon adaptations that followed have reused the same classic story Journey to the West, yet many consider this 1964 iteration to be the most original, fitting and memorable, The Golden Monkey Defeats a Demon【金猴降妖】 The Golden Monkey Defeats a Demon (Chinese: 金猴降妖), also referred as The Monkey King Conquers the Demon, is adapted from chapters of the Chinese classics Journey to the West, or Monkey in the Western world. The fiveepisode animation series tells the story of Monkey King Sun Wukong, who followed Monk Xuan Zang39。Journey to the West. The main character is Sun Wukong, aka the Monkey King, who rebels against the Jade Emperor of heaven. The stylized animation and drums and percussion acpaniment used in this film are heavily influenced bys feud with Nezha over his son39。movies. Nezha Conquers the Dragon King(Chinese: 哪吒鬧海)painting, including pavilions, ancient architecture, rippling streams and crowded markets, which fully demonstrate the unique beauty of China39。s contents on the stone wall of a white cloud cave in the mountains. He was then punished with guarding the book for life by the jade emperor for breaking heaven39。t want to steal food like other mice. Shuke became a pilot and Beita became a tank driver, and the pair met accidentally and became good friends. Then they befriended a boy named Pipilu. With the help of PiPilu, they cofounded an airline named Shuke Beita Airlines to help other animals. Although there are only 13 episodes in this series, the content is very pact and attractive. The animation shows the preciousness of friendship and how people should be brave when facing difficulties. Even adults recalling this animation today can still feel touched by some scenes. Secrets of the Heavenly Book Secrets of the Heavenly Book, (Chinese: 天書奇談)teacher in Turkish, is the respectful name for people who own wisdom and knowledge. The hero39。 violence, and lack of suitability for children39。FilmShanghais animation outpouring that are not to be missed. Let39?!     ?分  此時相應(yīng)齊次方程組的一般解為      (是自由未知量)分別令及,得齊次方程組的一個基礎(chǔ)解系     令,得非齊次方程組的一個特解     由此得原方程組的全部解為  (其中為任意常數(shù)) 4. 已知某種零件重量,采用新技術(shù)后,取了9個樣品,測得重量(單位:kg),已知方差不變,問平均重量是否仍為15()?解: 零假設(shè).由于已知,故選取樣本函數(shù)                       已知,經(jīng)計算得     ,         由已知條件,故接受零假設(shè),即零件平均重量仍為15. 1已知,其中,求.解:利用初等行變換得              即         由矩陣乘法運算得     的全部解.解: 將方程組的增廣矩陣化為階梯形       方程組的一般解為      (其中為自由未知量) 令=0,得到方程的一個特解. 方程組相應(yīng)的齊次方程的一般解為   (其中為自由未知量)令=1,得到方程的一個基礎(chǔ)解系. 于是,方程組的全部解為 (其中為任意常數(shù)) 3. 設(shè),求和.(其中,)解:設(shè)      == 4. 某一批零件重量,隨機抽取4個測得重量(單位:千克), , , ,可否認為這批零件的平均重量為15千克(已知)?解:零假設(shè).由于已知,故選取樣本函數(shù)               經(jīng)計算得            ,已知,故接受零假設(shè),即可以認為這批零件的平均重量為15千克四、證明題 1. 設(shè)是階矩陣,可逆,且,試證:.證明:在的兩端右乘,得     上式左端為 右端為 故有 證畢   2. 設(shè),是同階對稱矩陣,試證:也是對稱矩陣.證明:因 故可知是對稱矩陣.證畢3. 可逆的對稱矩陣的逆矩陣也是對稱矩陣.證明:設(shè)可逆,且則,所以也是對稱矩陣. 證畢4. 設(shè)是線性無關(guān)的,證明, 也線性無關(guān). 證明: 設(shè)有一組數(shù),使得 成立,即,由已知線性無關(guān),故有該方程組只有零解,得,故是線性無關(guān)的 證畢5. 設(shè),是兩個隨機事件,試證:.證明:由事件的關(guān)系可知     而,故由加法公式和乘法公式可知      證畢6. 已知隨機事件,滿足,試證:.證明:已知,由事件的關(guān)系可知     而,故由概率的性質(zhì)可知     即     證畢7. 設(shè)隨機事件,滿足,試證:.證明: 由可知,因此得,故     由因為,故有      證畢8. 設(shè)隨機變量的均值、方差都存在,且,試證:隨機變量的均值為0.證明: 結(jié)論得證. ⒎對任意方陣,試證是對稱矩陣.證明: 是對稱矩陣 ⒏若是階方陣,且,試證或. 證明: 是階方陣,且 或 ⒐若是正交矩陣,試證也是正交矩陣.證明: 是正交矩陣 即是正交矩陣,為隨機事件,試證:.  證明:由事件的關(guān)系可知     而,故由概率的性質(zhì)可知     即      證畢  請您刪除一下內(nèi)容,O(∩_∩)O謝謝?。?!【China39。2. 當取何值時,線性方程組有解,在有解的情況下求方程組的全部解.解:將方程組的增廣矩陣化為階梯形     由此可知當時,方程組無解?,F(xiàn)從這批產(chǎn)品中任取一件,求取出的產(chǎn)品是合格品的概率.解:設(shè)如下事件: :“產(chǎn)品來自甲廠” ?。骸爱a(chǎn)品來自乙廠” :“產(chǎn)品來自丙廠” :“產(chǎn)品是合格品”由全概公式有         由對立事件的關(guān)系可知     13. 一袋中有10個球,其中3個黑球7個白球.今從中依次無放回地抽取兩個,求第2次抽取出的是黑球的概率.解:設(shè)如下事件: :“第1次抽取出的是黑球” :“第2次抽取出的是黑球”顯然有,由全概公式得             14. 已知某批零件的加工由兩道工序完成,兩道工序的次品率彼此無關(guān),求這批零件的合格率.解: 設(shè)如下事件:?。骸暗谝坏拦ば蚣庸さ牧慵谴纹贰保骸暗诙拦ば蚣庸さ牧慵谴纹贰?:“零件是合格品”由事件的關(guān)系有            已知相互獨立,由加法公式得             由對立事件的關(guān)系可知  15. 設(shè),求;(2);(3).解: (1) (2) (3)16. 設(shè),試求⑴;⑵.(已知)解:⑴          …… ⑵         17. 設(shè),求⑴;⑵.解:⑴由期望的定義得      ⑵       18. 某車間生產(chǎn)滾珠,已知滾珠直徑服從正態(tài)分布.今從一批產(chǎn)品里隨機取出9個,若已知這批滾珠直徑的方差為,.解:由于已知,故選取樣本函數(shù)   已知,經(jīng)計算得     ,又由已知條
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