最小生成樹模型與實(shí)驗(yàn)-文庫吧資料
2025-04-23 02:04本頁面
【正文】 1 if we use link I, J。 LINK( CITY, CITY): DIST, ! The distance matrix。 ! U( I) = level of city I。 距離 kmATLCHICINHOULAATL07024548422396CHI702032410932136CIN454324011372180HOU8421093113701616LA2396213621081616 0 使用LINGO軟件編制此題的程序如下：MODEL:!Given the number of nodes and the distance between them, finding the shortest total distance of links on the network to connect all the nodes is the classic problem called minimal spanning tree (MST). This model finds the (MST) connecting Atlanta, Chicago, Cincinnati, Houston, and LA so that messages can be sent from Atlanta (base) to other cities through the network at minimum cost。例6 已知五個(gè)城市Atlanta, Chicago, Cincinnati, Houston 和 。167。END使用Solve求解獲得如下結(jié)果：, X(1,2)=1, X(2,3)=1, X(3,4)=1,X(4,5)=1, 其它X(I,J)=0。 U( K) = N 1 ( N 2) * X( 1, K)。 ! The level of a city except the base is at least 1 but no more than N1, and is 1 if it links to the base。 FOR( LINK: BIN( X)。 ! Make the X39。 ! There must be an arc out of city 1。 )。 ! If there are 2 disjoint tours from 1 city to another, we can remove a link without breaking connections. Note: These are not very powerful for large problems。 FOR( CITY( K)| K GT 1: ! It must be entered。 MIN = SUM( LINK: DIST * X)。 N = SIZE( CITY)。!from E。 4 3 1 0 2 !from D。 1 0 2 3 5 !from B。 !to: A B C D E。 ENDSETS DATA: ! Distance matrix need not be symmetric。 X。
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