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化學(xué)反應(yīng)動(dòng)力學(xué)(2)(參考版)

2025-01-16 10:27本頁(yè)面
  

【正文】 。 本章小結(jié) 1化學(xué)反應(yīng)動(dòng)力學(xué)方程,濃度效應(yīng)和溫度效應(yīng)。 RBAVVVRaRRdRRVRSBASBdBVBaBBAdAVAaAApkkrRRkkrRBAkpkrBBkpkrAARBA???????????????????????????????? ??????? ??????? ??????? ??????-=為表面空白活性位,且其中例如:有如下一反應(yīng)1氣固相催化反應(yīng)本征動(dòng)力學(xué) ? ?? ?2111,1,1,10RRBBAARBABAsARRBBAAVRRBBAARRRRRBBAABBBRRBBAAAAARBApKpKpKKpppKKkrpKpKpKpKpKpKpKpKpKpKpKpKpKpKpKrrr??????????????????????????????-可得動(dòng)力學(xué)表達(dá)式為代入表面反應(yīng)速率方程,可解得即平衡,步時(shí),其它各步達(dá)反應(yīng)當(dāng)反應(yīng)步驟為速率控制????氣固相催化反應(yīng)本征動(dòng)力學(xué) RBAVVVRaRRdRRVRSBASBdBVBaBBAdAVAaAApkkrRRkkrRBAkpkrBBkpkrAA???????????????????????????????? ??????? ??????? ??????? ????-=為表面空白活性位,且其中1當(dāng) A的吸附為速率控制步驟 RBA ??反應(yīng)氣固相催化反應(yīng)本征動(dòng)力學(xué) RRBBBBRRVVRRVBBBBVRRVRRVBBBBRRBAVVRRdRVRaRRBBRVBBVRssBVRssAVBBVdBBaBBpKpKpKKpKpKpKpKKpKpKpKpKKpKkpkpKKpKkkkkpKkpk??????????????????????????11111?????????????????????????? ?? ?RRBBBBRRBBARRAaARRBBBBRRBBRRdAAaAAVBBRRdAAaABBVRRdAVAaABBRdAVAaAAdAVAaAAAVpKpKpKKpKpKKKpKpkpKpKpKKpKpKKpKkpkrpKKpKkpkpKKpKkpkpKKkpkkpkrA???????????????????????????????????11--:的吸附速率方程式中得代入和將?????????式中:代入和將==以及==可解得=步驟,則有:的吸附過程為速率控制若-=為表面空白活性位,且其中例如有如下一反應(yīng)VRAVRRdRVRaRRRSRSARRAVVVRaRRdRRRSASAdAVAaAApKkpkKkkrrApkkrRRkkrRAkpkrAARA?????????????????????????????????? ?????? ?????? ????01RRRRARRAaAARRRRRRdAAaAVRRdAVAaARdAVAaAAdAVAaAARRRRVpKKpKKKpKpkrpKKpKKpKkpkKpKkpkKkpkkpkrApKKpK???????????????1111)()=(-===)(-的吸附速率方程得:代入???????:01式中代入和將==以及==可解得=步驟,則有:的脫附過程為速率控制若-=為表面空白活性位,且其中例如有如下一反應(yīng)VRAVAAsAsRVAAdAVAaAAARAVVVRaRRdRRRSASAdAVAaAApKKkkpKkpkrrRpkkrRRkkrRAkpkrAARA?????????????????????????????????? ?????? ?????? ?????
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