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單純形算法matlab編程報告-資料下載頁

2025-07-22 10:08本頁面
  

【正文】 panbieshu = 2 1 1 0 0 z = 2 k = 1 確定下標并選擇進基變量和離基變量為ans = 6 4 x(1)進基,x(5)離基B = 1 1 0 1 cB = 0 2 w = 0 2 panbieshu = 0 7 1 0 2 z = 1 k = 3 確定下標并選擇進基變量和離基變量為ans = 2 4 x(3)進基,x(4)離基B = 2 1 1 1 cB = 1 2 w = 1/3 5/3 panbieshu = 0 6 0 1/3 5/3 z = 0 k = 1 確定下標并選擇進基變量和離基變量為ans = 1/0 4 已找到最優(yōu)解!X = 14/3 0 0 0 0 X = 14/3 0 2/3 0 0 基向量為:X = 14/3 0 2/3 0 0 目標函數(shù)值為:f = 26/3
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