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精品課件大學(xué)物理2(雙語(yǔ))-資料下載頁(yè)

2025-04-17 15:54本頁(yè)面

【導(dǎo)讀】連續(xù)時(shí)間單位沖激信號(hào)。持續(xù)時(shí)間無(wú)窮小,瞬間幅度無(wú)窮大,涵蓋面積恒為

  

【正文】 tftyththtfty???????)()()( 2121 ???? ?????? thtxty)()()( ][][][ thtxty mnmn ???Communitive Associative Distributive Delay accumulation Derivative accumulation )()()()()]()([:.1 212121 tfdtdtftftfdtdtftfdtda t i o nd i f f e r e n t i ?????)()()()()]()([i 212121 tfdfdftfdffe gr at i on ttt ????? ??? ?????? ???????:)()()( )()()( )(2)(1)(21tftftyt h entftftyw h eninin ????? ,)1(21)1(212)1(121))()(39。( )()(39。)(39。)()()(:??????????tftftftftftftftfe x a m p l eCT convolution Differentiation and Integration of convolution convolution properties ?? )()(.1 ttf ? )(tf??? )()( 0tttf ? )( 0ttf ?)()()( 2121 tttfttttf ?????? ? shifting if f1(t) ? f2(t) = y(t) then f1(t ? t1) ? f2(t ? t2) = y(t ? t1 ? t2) )()( 2211 ttfttfSo l ut i on ???:??? dttftf )()( 2211 ???? ? ???dxxtttfxfxt)()( 21211???? ? ??????)( 21 ttty ????????dfttfttfttft)()()()()()()(.4 )1()1(? ??????????)()(.3 39。 ttf ?? )()(39。 ttf ??? )(39。 tf?)()()( )()( tfttfSo nn ?? ?   21)()()()(.52121??????????????tetetetettttconvolution properties Operator solution for convolution )()()()()()()()()()(212121tpHpHtpHtpHtftfty????????   )()( ttttEx a m p l e nm ?? ?:)(!)(! 11 tpntpmnm ?? ?? ??)(!!2 tpnmnm ????)()!1(!! 1 ttnmnm nm ??????        )(!)(!)()(11ttpnttpmthpHnnmm????Differentiation operator of convolution Example: y(t) = f(t) ? h(t) )( tft101)( tht201)1()( ?? ththt20 1311?? ?dtththththpthttpthtpfptyt)]1()([)]1()([1)()]1()([1)]()([1)(?????????????????)( tyt2011 3t t?3Example for TimeDomain Analysis of ContinuousTime systems 一 .系統(tǒng)的時(shí)域求解 二 . 指數(shù)信號(hào)系統(tǒng) 。求全響應(yīng)其中:設(shè)例)(,)()(,),()(11tytekthjstetfnitisti???????????0)(1?? ??tectynitixi    解: ???????nitistf tektethtftyi1)()()()()( ?? ??????nitstii teeski1)(][ ???? ?? ???????ninitstiitifxii eeskectytyty1 1][)()()(???     全響應(yīng)stni iitni iii eskeskci ???? ?????11][???固有響應(yīng) 強(qiáng)制響應(yīng) 。求例:)()()(,)(1tytekthjsAetfnitist i?????? ??? ?? ?????????? ???? dtekAethtftynititsfi ])([)()()(:1)(解][10)(? ???? ??nisist dekAe i ??????? )(,]R e []R e [ tys fi 則① ??spststni iistfiphAesHAeskAetys???????? )()(][)(,]R e []R e [1 ??? 則②???? ??tectynitixi    1)( ?忽略)(]R e []R e [ tys xi ???)()(]R e []R e [)(Ae)(m a x sHAetyspHtfstist???響應(yīng)滿足時(shí),系統(tǒng)為無(wú)時(shí)限指數(shù)信號(hào)當(dāng)輸入?
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