微機原理與接口技術習題(編輯修改稿)
2025-04-21 01:55 本頁面
【文章內(nèi)容簡介】 [DATA]=0A50H (5)(AL)=04H SF=0 PF=0 ZF=0(6)(AL)=0C5H SF=1 PF=1 ZF=0(7)(AL)=3BH SF=0 PF=0 ZF=0(8)(AL)=0C4H SF=1 PF=0 ZF=0311 【答】：(IP)=009AH (CS)=2000H(SP)=0F178H [SP]=F8H [SP+1]=3DH [SP+2]=05H [SP+3]=04H312 【答】：(1) OF=0 SF=0 ZF=1 AF=1 PF=1 CF=1(2) OF=0 SF=0 ZF=0 AF=0 PF=0 CF=0(3) OF=1 SF=0 ZF=0 AF=0 PF=0 CF=0(4) OF=1 SF=0 ZF=0 AF=0 PF=0 CF=144【答】：變量用來定義存放在存儲單元中的數(shù)據(jù)。有三重屬性：段屬性、偏移地址屬性、類型屬性。46【答】：標號是指指令語句所在地址的符號表示。有三重屬性：段屬性、偏移地址屬性、距離屬性。415【答】：DATA SEGMENT MBUF DB 12H,34H,56H,78H,90H COUNT EQU $MBUF ORG 0020H NBUF DB COUNT DUP(0)DATA ENDSSTACK1 SEGMENT STACK DW 20 DUP(?)STACK1 ENDSCODE SEGMENT ASSUME CS:CODE,DS:DATA,SS:STACK1START:MOV AX,DATA MOV DS,AX MOV BX,OFFSET MBUF ADD BX,COUNT1 MOV SI,OFFSET NBUF MOV CX,COUNTSAVE: MOV AL,[BX] MOV [SI],AL DEC BX INC SI DEC CX JNZ SAVE MOV AH,4CH INT 21HCODE ENDS END START 416【答】：DATA SEGMENT XX DB 2,0,2 COUNT EQU $XX ORG 0020H YY DB ?,?,?DATA ENDSCODE SEGMENT ASSUME CS:CODE,DS:DATASTART:MOV AX,DATA MOV DS,AX 。MOV BX,OFFSET XX LEA BX,XX MOV SI,OFFSET YY MOV CX,COUNTACUL: MOV AL,[BX] CMP AL,1 JGE BIGR CMP AL,1 JLE LOWER MOV AL,0 JMP SAVEBIGR: MOV AL,1 JMP SAVELOWER: MOV AL,1SAVE: MOV [SI],AL INC BX INC SI DEC CX JNZ ACUL MOV AH,4CH INT 21H CODE ENDS END START 417【答】：DATA SEGMENT RAMDATA DB 1,1,2,2,3,3,4,5,4,6,7,5,6,7,8,9 COUNT EQU $RAMDATA POSBUF DB COUNT DUP(0) NEGBUF DB COUNT DUP(0) POSNUM DB 0 NEGNUM DB 0DATA ENDSSTACK1 SEGMENT STACK DW 20 DUP(?) STACK1 ENDSCODE SEGMENT ASSUME CS:CODE,DS:DATA,SS:STACK1START:MOV AX,DATA MOV DS,AX LEA BX,RAMDATA MOV SI,OFFSET POSBUF MOV DI,OFFSET NEGBUF MOV CX,COUNTLOP: MOV AL,[BX] TEST AL,80H JS NEGATIVE CMP AL,0 JG POSITIVE JMP GOLOPNEGATIVE:MOV [DI],AL INC DI INC NEGNUM JMP GOLOPPOSITIVE:MOV [SI],AL INC SI INC POSNUM JMP GOLOP GO
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