[電腦基礎(chǔ)知識]c語言第一章(編輯修改稿)
2025-02-15 15:23 本頁面
【文章內(nèi)容簡介】 發(fā)散級數(shù)反例?????????????nkknnksn??17 ..)(31能改變但在級數(shù)收斂時其和可斂散性的有限項不影響其級數(shù)或加減改變性質(zhì) ???nnu.,11。1,1,2212111則其和不變?nèi)粼诩墧?shù)前再加兩項則其和為若去掉第一項級數(shù)反例?????????????n18 .0l i m41??????? nnnn uu 收斂若性質(zhì)????????????????????????????????????????11111111.)()4(.)(,)3(.,0lim)2(.,0lim)1(nnnnnnnnnnnnnnnnnnnnnnvuvuvuvuuuuu未必發(fā)散都發(fā)散，則和若一定發(fā)散發(fā)散，則收斂若未必收斂則若必發(fā)散則若注釋19 .)()(.3111收斂發(fā)散都和 ????????????nnnnnnn.)121(121.2。0)1(l i m)1(.11111發(fā)散發(fā)散收斂，發(fā)散，但反例?????????????????????nnnnnnnnnnn20 .1l i m)1l n (11發(fā)散則 ??????????????nnnnn nsnxdxs.131211131的斂散性判定調(diào)和級數(shù)例 ?? ???????? nnn? ?????????????????????nynxxynsn1,31,21,1,3,2,1,1,1312111時，則當(dāng)令解法 ?xy 1?oyx1 2 3 4 n 1?n21 ? ?..)(2100)(lim,.212212111222故調(diào)和級數(shù)發(fā)散這是不可能的于是設(shè)其和為若調(diào)和級數(shù)收斂，則可因為解法???????????????????nsssssnnnnnssnnnnn?22 .,11)1(14122的和求級數(shù)圖形的面積為且兩條拋物線所圍交點橫坐標(biāo)的絕對值為和設(shè)拋物線例?????????n nnnnuSSunxnynnxy23 .34)111(34limlim)111(34)1()1(3411)1(12.)1(111)1(111102222?????????????????????????????????????????????????????nknnk kknn nnnnunnkku
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